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Khan academy video on logarithms - 3

Simplify, without use of a calculator:

3 log 3 + log 125
  1. 125 can be written as 5 3 .

  2. 3 log 3 + log 125 = 3 log 3 + log 5 3 = 3 log 3 + 3 log 5 log a ( x b ) = b log a ( x )
  3. We cannot simplify any further. The final answer is:

    3 log 3 + 3 log 5

Simplify, without use of a calculator:

8 2 3 + log 2 32
  1. 8 can be written as 2 3 . 32 can be written as 2 5 .

  2. 8 2 3 + log 2 32 = ( 2 3 ) 2 3 + log 2 2 5
  3. We can use:

    log a ( x b ) = b log a ( x )
  4. ( 2 3 ) 2 3 + log 2 2 5 = ( 2 ) 3 2 3 + 5 log 2 2
  5. We can now use log a a = 1

  6. ( 2 ) 3 2 3 + 5 log 2 2 = ( 2 ) 2 + 5 ( 1 ) = 4 + 5 = 9
  7. The final answer is:

    8 2 3 + log 2 32 = 9

Write 2 log 3 + log 2 - log 5 as the logarithm of a single number.

  1. 2 log 3 + log 2 - log 5 = log 3 2 + log 2 - log 5

  2. = log ( 3 2 × 2 ÷ 5 )

  3. = log 3 , 6

Exponent rule: x b a = x a b

Solving simple log equations

In grade 10 you solved some exponential equations by trial and error, because you did not know the great power of logarithms yet. Now it is much easier to solve these equations by using logarithms.

For example to solve x in 25 x = 50 correct to two decimal places you simply apply the following reasoning. If the LHS = RHS then the logarithm of the LHS must be equal to the logarithm of the RHS. By applying Law 5, you will be able to use your calculator to solve for x .

Solve for x :    25 x = 50 correct to two decimal places.

  1. log 25 x = log 50

  2. x log 25 = log 50

  3. x = log 50 ÷ log 25

    x = 1 , 21533 . . . .

  4. x = 1 , 22

In general, the exponential equation should be simplified as much as possible. Then the aim is to make the unknown quantity (i.e. x ) the subject of the equation.

For example, the equation

2 ( x + 2 ) = 1

is solved by moving all terms with the unknown to one side of the equation and taking all constants to the other side of the equation

2 x · 2 2 = 1 2 x = 1 2 2

Then, take the logarithm of each side.

log ( 2 x ) = log ( 1 2 2 ) x log ( 2 ) = - log ( 2 2 ) x log ( 2 ) = - 2 log ( 2 ) Divide both sides by log ( 2 ) x = - 2

Substituting into the original equation, yields

2 - 2 + 2 = 2 0 = 1

Similarly, 9 ( 1 - 2 x ) = 3 4 is solved as follows:

9 ( 1 - 2 x ) = 3 4 3 2 ( 1 - 2 x ) = 3 4 3 2 - 4 x = 3 4 take the logarithm of both sides log ( 3 2 - 4 x ) = log ( 3 4 ) ( 2 - 4 x ) log ( 3 ) = 4 log ( 3 ) divide both sides by log ( 3 ) 2 - 4 x = 4 - 4 x = 2 x = - 1 2

Substituting into the original equation, yields

9 ( 1 - 2 ( - 1 2 ) ) = 9 ( 1 + 1 ) = 3 2 ( 2 ) = 3 4

Solve for x in 7 · 5 ( 3 x + 3 ) = 35

  1. There are two possible bases: 5 and 7. x is an exponent of 5.

  2. In order to eliminate 7, divide both sides of the equation by 7 to give:

    5 ( 3 x + 3 ) = 5
  3. log ( 5 ( 3 x + 3 ) ) = log ( 5 )
  4. ( 3 x + 3 ) log ( 5 ) = log ( 5 ) divide both sides of the equation by log ( 5 ) 3 x + 3 = 1 3 x = - 2 x = - 2 3
  5. 7 · 5 ( - 3 2 3 + 3 ) = 7 · 5 ( - 2 + 3 ) = 7 · 5 1 = 35

Exercises

Solve for x :

  1. log 3 x = 2
  2. 10 log 27 = x
  3. 3 2 x - 1 = 27 2 x - 1

Logarithmic applications in the real world

Logarithms are part of a number of formulae used in the Physical Sciences. There are formulae that deal with earthquakes, with sound, and pH-levels to mention a few. To work out time periods is growth or decay, logs are used to solve the particular equation.

A city grows 5% every 2 years. How long will it take for the city to triple its size?

  1. A = P ( 1 + i ) n Assume P = x , then A = 3 x . For this example n represents a period of 2 years, therefore the n is halved for this purpose.

  2. 3 = ( 1 , 05 ) n 2 log 3 = n 2 × log 1 , 05 ( using law 5 ) n = 2 log 3 ÷ log 1 , 05 n = 45 , 034
  3. So it will take approximately 45 years for the population to triple in size.

I have R12 000 to invest. I need the money to grow to at least R30 000. If it is invested at a compound interest rate of 13% per annum, for how long (in full years) does my investment need to grow ?

  1. A = P ( 1 + i ) n
  2. 30000 < 12000 ( 1 + 0 , 13 ) n 1 , 13 n > 5 2 n log ( 1 , 13 ) > log ( 2 , 5 ) n > log ( 2 , 5 ) ÷ log ( 1 , 13 ) n > 7 , 4972 ...
  3. In this case we round up, because 7 years will not yet deliver the required R 30 000. The investment need to stay in the bank for at least 8 years.

Exercises

  1. The population of a certain bacteria is expected to grow exponentially at a rate of 15 % every hour. If the initial population is 5 000, how long will it take for the population to reach 100 000 ?
  2. Plus Bank is offering a savings account with an interest rate if 10 % per annum compounded monthly. You can afford to save R 300 per month. How long will it take you to save R 20 000 ? (Give your answer in years and months)

End of chapter exercises

  1. Show that
    log a x y = log a ( x ) - log a ( y )
  2. Show that
    log a x b = log a ( x ) b
  3. Without using a calculator show that:
    log 75 16 - 2 log 5 9 + log 32 243 = log 2
  4. Given that 5 n = x and n = log 2 y
    1. Write y in terms of n
    2. Express log 8 4 y in terms of n
    3. Express 50 n + 1 in terms of x and y
  5. Simplify, without the use of a calculator:
    1. 8 2 3 + log 2 32
    2. log 3 9 - log 5 5
    3. 5 4 - 1 - 9 - 1 1 2 + log 3 9 2 , 12
  6. Simplify to a single number, without use of a calculator:
    1. log 5 125 + log 32 - log 8 log 8
    2. log 3 - log 0 , 3
  7. Given:     log 3 6 = a and log 6 5 = b
    1. Express log 3 2 in terms of a .
    2. Hence, or otherwise, find log 3 10 in terms of a and b .
  8. Given:     p q k = q p - 1 Prove:     k = 1 - 2 log q p
  9. Evaluate without using a calculator: ( log 7 49 ) 5 + log 5 1 125 - 13 log 9 1
  10. If log 5 = 0 , 7 , determine, without using a calculator :
    1. log 2 5
    2. 10 - 1 , 4
  11. Given:        M = log 2 ( x + 3 ) + log 2 ( x - 3 )
    1. Determine the values of x for which M is defined.
    2. Solve for x if M = 4 .
  12. Solve:        x 3 log x = 10 x 2 (Answer(s) may be left in surd form, if necessary.)
  13. Find the value of ( log 27 3 ) 3 without the use of a calculator.
  14. Simplify By using a calculator: log 4 8 + 2 log 3 27
  15. Write log 4500 in terms of a and b if 2 = 10 a and 9 = 10 b .
  16. Calculate:        5 2006 - 5 2004 + 24 5 2004 + 1
  17. Solve the following equation for x without the use of a calculator and using the fact that 10 3 , 16 :
    2 log ( x + 1 ) = 6 log ( x + 1 ) - 1
  18. Solve the following equation for x : 6 6 x = 66    (Give answer correct to 2 decimal places.)

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Source:  OpenStax, Siyavula textbooks: grade 12 maths. OpenStax CNX. Aug 03, 2011 Download for free at http://cnx.org/content/col11242/1.2
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