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When you add or subtract the same quantity from both sides of an equation, you still have equality.

We introduced the Subtraction Property of Equality earlier by modeling equations with envelopes and counters. [link] models the equation x + 3 = 8 .

An envelope and three yellow counters are shown on the left side. On the right side are eight yellow counters.

The goal is to isolate the variable on one side of the equation. So we ‘took away’ 3 from both sides of the equation and found the solution x = 5 .

Some people picture a balance scale, as in [link] , when they solve equations.

Three balance scales are shown. The top scale has one red weight on each side and is balanced. Beside it is “1 mass on each side equals balanced.” The next scale has two weights on each side and is balanced. Beside it is “2 masses on each side equals balanced.” The bottom scale has one weight on the left and two on the right. The right side is lower than the left. Beside the image is “1 mass on one side and 2 masses on the other equals unbalanced.”

The quantities on both sides of the equal sign in an equation are equal, or balanced. Just as with the balance scale, whatever you do to one side of the equation you must also do to the other to keep it balanced.

Let’s review how to use Subtraction and Addition Properties of Equality to solve equations. We need to isolate the variable on one side of the equation. And we check our solutions by substituting the value into the equation to make sure we have a true statement.

Solve: x + 11 = −3 .

Solution

To isolate x , we undo the addition of 11 by using the Subtraction Property of Equality.

.
Subtract 11 from each side to "undo" the addition. .
Simplify. .
Check: .
Substitute x = −14 . .
.

Since x = −14 makes x + 11 = −3 a true statement, we know that it is a solution to the equation.

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Solve: x + 9 = −7 .

x = −16

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Solve: x + 16 = −4 .

x = −20

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In the original equation in the previous example, 11 was added to the x , so we subtracted 11 to ‘undo’ the addition. In the next example, we will need to ‘undo’ subtraction by using the Addition Property of Equality .

Solve: m 4 = −5 .

Solution

.
Add 4 to each side to "undo" the subtraction. .
Simplify. .
Check: .
Substitute m = −1 . .
.
The solution to m 4 = −5 is m = −1 .
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Solve: n 6 = −7 .

−1

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Solve: x 5 = −9 .

−4

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Now let’s review solving equations with fractions.

Solve: n 3 8 = 1 2 .

Solution

.
Use the Addition Property of Equality. .
Find the LCD to add the fractions on the right. .
Simplify .
Check: .
. .
Subtract. .
Simplify. .
The solution checks.
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Solve: p 1 3 = 5 6 .

p = 7 6

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Solve: q 1 2 = 1 6 .

q = 2 3

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In Solve Equations with Decimals , we solved equations that contained decimals. We’ll review this next.

Solve a 3.7 = 4.3 .

Solution

.
Use the Addition Property of Equality. .
Add. .
Check: .
Substitute a = 8 . .
Simplify. .
The solution checks.
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Solve: b 2.8 = 3.6 .

b = 6.4

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Solve: c 6.9 = 7.1 .

c = 14

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Solve equations that need to be simplified

In the examples up to this point, we have been able to isolate the variable with just one operation. Many of the equations we encounter in algebra will take more steps to solve. Usually, we will need to simplify one or both sides of an equation before using the Subtraction or Addition Properties of Equality. You should always simplify as much as possible before trying to isolate the variable.

Solve: 3 x 7 2 x 4 = 1 .

Solution

The left side of the equation has an expression that we should simplify before trying to isolate the variable.

.
Rearrange the terms, using the Commutative Property of Addition. .
Combine like terms. .
Add 11 to both sides to isolate x . .
Simplify. .
Check.
Substitute x = 12 into the original equation.
The top line shows 3x minus 7 minus 2x minus 4 equals 1. Below this is 3 times a red 12 minus 7 minus 2 times a red 12 minus 4 equals 1. Next is 36 minus 7 minus 24 minus 4 equals 1. Below is 29 minus 24 minus 4 equals 1. Next is 5 minus 4 equals 1. Last is 1 equals 1.

The solution checks.

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Solve: 8 y 4 7 y 7 = 4 .

y = 15

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Solve: 6 z + 5 5 z 4 = 3 .

z = 2

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Solve: 3 ( n 4 ) 2 n = −3 .

Solution

The left side of the equation has an expression that we should simplify.

.
Distribute on the left. .
Use the Commutative Property to rearrange terms. .
Combine like terms. .
Isolate n using the Addition Property of Equality. .
Simplify. .
Check.
Substitute n = 9 into the original equation.
The top line says 3 times parentheses n minus 4 minus 2n equals negative 3. The next line says 3 times parentheses red 9 minus 3 minus 2 times red 9 equals negative 3. The next line says 3 times 5 minus 18 equals negative 3. Below this is 15 minus 18 equals negative 3. Last is negative 3 equals negative 3.
The solution checks.
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Practice Key Terms 1

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Source:  OpenStax, Prealgebra. OpenStax CNX. Jul 15, 2016 Download for free at http://legacy.cnx.org/content/col11756/1.9
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