# 2.2 Graphs of linear functions  (Page 10/15)

 Page 10 / 15

$\begin{array}{c}3y+x=12\\ -y=8x+1\end{array}$

neither parallel or perpendicular

$\begin{array}{c}3y+4x=12\\ -6y=8x+1\end{array}$

$\begin{array}{c}6x-9y=10\\ 3x+2y=1\end{array}$

perpendicular

$\begin{array}{c}y=\frac{2}{3}x+1\\ 3x+2y=1\end{array}$

$\begin{array}{c}y=\frac{3}{4}x+1\\ -3x+4y=1\end{array}$

parallel

For the following exercises, find the x - and y- intercepts of each equation

$f\left(x\right)=-x+2$

$g\left(x\right)=2x+4$

;

$h\left(x\right)=3x-5$

$k\left(x\right)=-5x+1$

;

$-2x+5y=20$

$7x+2y=56$

;

For the following exercises, use the descriptions of each pair of lines given below to find the slopes of Line 1 and Line 2. Is each pair of lines parallel, perpendicular, or neither?

• Line 1: Passes through $\left(0,6\right)$ and $\left(3,-24\right)$
• Line 2: Passes through $\left(-1,19\right)$ and $\left(8,-71\right)$
• Line 1: Passes through $\left(-8,-55\right)$ and $\left(10,\text{\hspace{0.17em}}89\right)$
• Line 2: Passes through $\left(9,-44\right)$ and $\left(4,-14\right)$

• Line 1: Passes through $\left(2,3\right)$ and $\left(4,-1\right)$
• Line 2: Passes through $\left(6,3\right)$ and $\left(8,5\right)$
• Line 1: Passes through $\left(1,7\right)$ and $\left(5,5\right)$
• Line 2: Passes through $\left(-1,-3\right)$ and $\left(1,1\right)$

• Line 1: Passes through $\left(0,5\right)$ and $\left(3,3\right)$
• Line 2: Passes through $\left(1,-5\right)$ and $\left(3,-2\right)$
• Line 1: Passes through $\left(2,5\right)$ and $\left(5,-1\right)$
• Line 2: Passes through $\left(-3,7\right)$ and $\left(3,-5\right)$

Write an equation for a line parallel to $f\left(x\right)=-5x-3$ and passing through the point

Write an equation for a line parallel to $g\left(x\right)=3x-1$ and passing through the point $\left(4,9\right).$

$g\left(x\right)=3x-3$

Write an equation for a line perpendicular to $h\left(t\right)=-2t+4$ and passing through the point

Write an equation for a line perpendicular to $p\left(t\right)=3t+4$ and passing through the point $\left(3,1\right).$

$p\left(t\right)=-\frac{1}{3}t+2$

Find the point at which the line $f\left(x\right)=-2x-1$ intersects the line $g\left(x\right)=-x.$

Find the point at which the line $f\left(x\right)=2x+5$ intersects the line $g\left(x\right)=-3x-5.$

$\left(-2,1\right)$

Use algebra to find the point at which the line intersects the line $h\left(x\right)=\frac{9}{4}x\text{\hspace{0.17em}}\text{\hspace{0.17em}}+\text{\hspace{0.17em}}\text{\hspace{0.17em}}\frac{73}{10}.$

Use algebra to find the point at which the line $f\left(x\right)=\frac{7}{4}x\text{\hspace{0.17em}}\text{\hspace{0.17em}}+\text{\hspace{0.17em}}\text{\hspace{0.17em}}\frac{457}{60}$ intersects the line $g\left(x\right)=\frac{4}{3}x\text{\hspace{0.17em}}\text{\hspace{0.17em}}+\text{\hspace{0.17em}}\text{\hspace{0.17em}}\frac{31}{5}.$

$\left(-\frac{17}{5},\frac{5}{3}\right)$

## Graphical

For the following exercises, the given linear equation with its graph in [link] .

$f\left(x\right)=-x-1$

$f\left(x\right)=-2x-1$

F

$f\left(x\right)=-\frac{1}{2}x-1$

$f\left(x\right)=2$

C

$f\left(x\right)=2+x$

$f\left(x\right)=3x+2$

A

For the following exercises, sketch a line with the given features.

An x -intercept of and y -intercept of

An x -intercept of and y -intercept of

A y -intercept of and slope $-\frac{3}{2}$

A y -intercept of and slope $\frac{2}{5}$

Passing through the points and

Passing through the points and

For the following exercises, sketch the graph of each equation.

$f\left(x\right)=-2x-1$

$g\left(x\right)=-3x+2$

$h\left(x\right)=\frac{1}{3}x+2$

$k\left(x\right)=\frac{2}{3}x-3$

$f\left(t\right)=3+2t$

$p\left(t\right)=-2\text{\hspace{0.17em}}+\text{\hspace{0.17em}}3t$

$x=3$

$x=-2$

$r\left(x\right)=4$

$q\left(x\right)=3$

$4x=-9y+36$

$\frac{x}{3}-\frac{y}{4}=1$

$3x-5y=15$

$3x=15$

$3y=12$

If $g\left(x\right)$ is the transformation of $f\left(x\right)=x$ after a vertical compression by $\frac{3}{4},$ a shift right by 2, and a shift down by 4

1. Write an equation for $g\left(x\right).$
2. What is the slope of this line?
3. Find the y- intercept of this line.

• $g\left(x\right)=0.75x-5.5\text{}$
• 0.75
• $\left(0,-5.5\right)$

If $g\left(x\right)$ is the transformation of $f\left(x\right)=x$ after a vertical compression by $\frac{1}{3},$ a shift left by 1, and a shift up by 3

1. Write an equation for $g\left(x\right).$
2. What is the slope of this line?
3. Find the y- intercept of this line.

For the following exercises,, write the equation of the line shown in the graph.

$y=\text{3}$

$x=-3$

For the following exercises, find the point of intersection of each pair of lines if it exists. If it does not exist, indicate that there is no point of intersection.

$\begin{array}{c}y=\frac{3}{4}x+1\\ -3x+4y=12\end{array}$

no point of intersection

$\begin{array}{c}2x-3y=12\\ 5y+x=30\end{array}$

$\begin{array}{c}2x=y-3\\ y+4x=15\end{array}$

$\begin{array}{c}x-2y+2=3\\ x-y=3\end{array}$

$\begin{array}{c}5x+3y=-65\\ x-y=-5\end{array}$

## Extensions

Find the equation of the line parallel to the line $g\left(x\right)=-0.\text{01}x\text{\hspace{0.17em}}\text{+}\text{\hspace{0.17em}}\text{2}\text{.01}$ through the point

Find the equation of the line perpendicular to the line $g\left(x\right)=-0.\text{01}x\text{+2}\text{.01}$ through the point

$y=100x-98$

For the following exercises, use the functions

Find the point of intersection of the lines $f$ and $g.$

Where is $f\left(x\right)$ greater than $g\left(x\right)?$ Where is $g\left(x\right)$ greater than $f\left(x\right)?$

$x<\frac{1999}{201}x>\frac{1999}{201}$

## Real-world applications

A car rental company offers two plans for renting a car.

• Plan A: $30 per day and$0.18 per mile
• Plan B: $50 per day with free unlimited mileage How many miles would you need to drive for plan B to save you money? A cell phone company offers two plans for minutes. • Plan A:$20 per month and $1 for every one hundred texts. • Plan B:$50 per month with free unlimited texts.

How many texts would you need to send per month for plan B to save you money?

Less than 3000 texts

A cell phone company offers two plans for minutes.

• Plan A: $15 per month and$2 for every 300 texts.
• Plan B: $25 per month and$0.50 for every 100 texts.

How many texts would you need to send per month for plan B to save you money?

can I get some pretty basic questions
In what way does set notation relate to function notation
Ama
is precalculus needed to take caculus
It depends on what you already know. Just test yourself with some precalculus questions. If you find them easy, you're good to go.
Spiro
the solution doesn't seem right for this problem
what is the domain of f(x)=x-4/x^2-2x-15 then
x is different from -5&3
Seid
how to prroved cos⁴x-sin⁴x= cos²x-sin²x are equal
Don't think that you can.
Elliott
how do you provided cos⁴x-sin⁴x = cos²x-sin²x are equal
What are the question marks for?
Elliott
Someone should please solve it for me Add 2over ×+3 +y-4 over 5 simplify (×+a)with square root of two -×root 2 all over a multiply 1over ×-y{(×-y)(×+y)} over ×y
For the first question, I got (3y-2)/15 Second one, I got Root 2 Third one, I got 1/(y to the fourth power) I dont if it's right cause I can barely understand the question.
Is under distribute property, inverse function, algebra and addition and multiplication function; so is a combined question
Abena
find the equation of the line if m=3, and b=-2
graph the following linear equation using intercepts method. 2x+y=4
Ashley
how
Wargod
what?
John
ok, one moment
UriEl
how do I post your graph for you?
UriEl
it won't let me send an image?
UriEl
also for the first one... y=mx+b so.... y=3x-2
UriEl
y=mx+b you were already given the 'm' and 'b'. so.. y=3x-2
Tommy
Please were did you get y=mx+b from
Abena
y=mx+b is the formula of a straight line. where m = the slope & b = where the line crosses the y-axis. In this case, being that the "m" and "b", are given, all you have to do is plug them into the formula to complete the equation.
Tommy
thanks Tommy
Nimo
0=3x-2 2=3x x=3/2 then . y=3/2X-2 I think
Given
co ordinates for x x=0,(-2,0) x=1,(1,1) x=2,(2,4)
neil
"7"has an open circle and "10"has a filled in circle who can I have a set builder notation
x=-b+_Гb2-(4ac) ______________ 2a
I've run into this: x = r*cos(angle1 + angle2) Which expands to: x = r(cos(angle1)*cos(angle2) - sin(angle1)*sin(angle2)) The r value confuses me here, because distributing it makes: (r*cos(angle2))(cos(angle1) - (r*sin(angle2))(sin(angle1)) How does this make sense? Why does the r distribute once
so good
abdikarin
this is an identity when 2 adding two angles within a cosine. it's called the cosine sum formula. there is also a different formula when cosine has an angle minus another angle it's called the sum and difference formulas and they are under any list of trig identities
strategies to form the general term
carlmark
consider r(a+b) = ra + rb. The a and b are the trig identity.
Mike
How can you tell what type of parent function a graph is ?
generally by how the graph looks and understanding what the base parent functions look like and perform on a graph
William
if you have a graphed line, you can have an idea by how the directions of the line turns, i.e. negative, positive, zero
William
y=x will obviously be a straight line with a zero slope
William
y=x^2 will have a parabolic line opening to positive infinity on both sides of the y axis vice versa with y=-x^2 you'll have both ends of the parabolic line pointing downward heading to negative infinity on both sides of the y axis
William
y=x will be a straight line, but it will have a slope of one. Remember, if y=1 then x=1, so for every unit you rise you move over positively one unit. To get a straight line with a slope of 0, set y=1 or any integer.
Aaron
yes, correction on my end, I meant slope of 1 instead of slope of 0
William
what is f(x)=
I don't understand
Joe
Typically a function 'f' will take 'x' as input, and produce 'y' as output. As 'f(x)=y'. According to Google, "The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain."
Thomas
Sorry, I don't know where the "Â"s came from. They shouldn't be there. Just ignore them. :-)
Thomas
Darius
Thanks.
Thomas
Â
Thomas
It is the Â that should not be there. It doesn't seem to show if encloses in quotation marks. "Â" or 'Â' ... Â
Thomas
Now it shows, go figure?
Thomas
what is this?
i do not understand anything
unknown
lol...it gets better
Darius
I've been struggling so much through all of this. my final is in four weeks 😭
Tiffany
this book is an excellent resource! have you guys ever looked at the online tutoring? there's one that is called "That Tutor Guy" and he goes over a lot of the concepts
Darius
thank you I have heard of him. I should check him out.
Tiffany
is there any question in particular?
Joe
I have always struggled with math. I get lost really easy, if you have any advice for that, it would help tremendously.
Tiffany
Sure, are you in high school or college?
Darius
Hi, apologies for the delayed response. I'm in college.
Tiffany
how to solve polynomial using a calculator