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Summary

In this module, you learned how to darken, brighten, and tint the colors in a Picture object.

What's next?

You will probably learn more than you already know about interfaces, arrays of type Object, etc., in the next module.

While not a requirement of the course, you can select the following links to view optional online video lectures on the material in thismodule.

Miscellaneous

This section contains a variety of miscellaneous information.

Housekeeping material
  • Module name: Java OOP: Darkening, Brightening, and Tinting the Colors in a Picture
  • File: Java3018.htm
  • Published: 08/01/12
Disclaimers:

Financial : Although the Connexions site makes it possible for you to download a PDF file for thismodule at no charge, and also makes it possible for you to purchase a pre-printed version of the PDF file, you should beaware that some of the HTML elements in this module may not translate well into PDF.

I also want you to know that, I receive no financial compensation from the Connexions website even if you purchase the PDF version of the module.

In the past, unknown individuals have copied my modules from cnx.org, converted them to Kindle books, and placed them for sale on Amazon.com showing me as the author. I neither receive compensation for those sales nor do I know who doesreceive compensation. If you purchase such a book, please be aware that it is a copy of a module that is freelyavailable on cnx.org and that it was made and published without my prior knowledge.

Affiliation : I am a professor of Computer Information Technology at Austin Community College in Austin, TX.

Complete program listing

A complete listing of the program discussed in this module is shown in Listing 10 below.

Listing 10 . Complete program listing.
/*File Prob04 Copyright 2008 R.G.Baldwin *********************************************************/import java.awt.Color; public class Prob04{public static void main(String[] args){Prob04Runner obj = new Prob04Runner(); obj.run();}//end main }//end class Prob04//======================================================// class Prob04Runner{public Prob04Runner(){//constructor System.out.println("Display your name here.");}//end constructor //----------------------------------------------------//public void run(){ Picture skater = new Picture("Prob04a.bmp");skater.explore(); skater = crop(skater,6,59,392,293);Picture hole = new Picture("Prob04b.bmp"); hole.explore();hole = crop(hole,6,59,392,293); Picture snowScene = new Picture("Prob04c.jpg");snowScene.explore(); snowScene = crop(snowScene,6,59,392,293);//Make all the pixels darker in the snow scene except // for those in the location of the hole. Make them// brighter. darkenBackground(hole,snowScene);//Apply a red tint to the skater redTint(skater);//Draw the skater on the snowScene. greenScreenDraw(skater,snowScene,0,0);//Display students name on the final output and // display it.snowScene.addMessage("Display your name here.",10,15); snowScene.explore();System.out.println(snowScene); }//end run method//----------------------------------------------------// //Assumes the source has a pure green background.// Applies a red tint to every pixel that is not pure // green.private void redTint(Picture pic){ Pixel[]pixels = pic.getPixels(); Color color = null;int red = 0; int green = 0;int blue = 0; for(int cnt = 0;cnt<pixels.length;cnt++){ color = pixels[cnt].getColor(); //Apply a red tint to all non-green pixelsif(!(color.equals(Color.GREEN))){ //Increase the value of the red componentred = color.getRed(); if(red*1.25<255){ red = (int)(red * 1.25);}else{ red = 255;}//end else //Decrease the value of blue and greengreen = (int)(color.getGreen()*0.8); blue = (int)(color.getBlue()*0.8);//Apply the new color to the pixel. pixels[cnt].setColor(new Color(red,green,blue)); }//end if}//end for loop }//end redTint//----------------------------------------------------// //Assumes the pattern image has a pure green background.// Assumes that the pattern and the destination have the // same dimensions. Darkens every pixel in the// destination that is at the location of a green pixel // in the pattern. Applies a red tint to every pixel// in the destination that is at the location of a // non-green pixel in the patternprivate void darkenBackground( Picture pattern,Picture dest){ Pixel[]patternPixels = pattern.getPixels(); Pixel[]destPixels = dest.getPixels(); Color color = null;int red = 0; int green = 0;int blue = 0; for(int cnt = 0;cnt<patternPixels.length;cnt++){ color = patternPixels[cnt].getColor(); if(color.equals(Color.GREEN)){//Darken corresponding pixel in the destination. color = destPixels[cnt].getColor(); destPixels[cnt].setColor(color.darker()); }else{//Apply a red tint to the corresponding pixel in // the destination.color = destPixels[cnt].getColor();red = color.getRed(); if(red*1.25<255){ red = (int)(red * 1.25);}else{ red = 255;}//end else green = (int)(color.getGreen() * 0.8);blue = (int)(color.getBlue() * 0.8); destPixels[cnt].setColor(new Color(red,green,blue)); }//end else}//end for loop }//end darkenBackground//----------------------------------------------------// //Assumes a source image with a pure green background.// Copies all non-green pixels from the source image to // the destination image at the location explained// below. Note that JPEG images typically won't have // a pure green background even if they had a pure// green background before being compressed into the // JPEG format. BMP images work well for this.private void greenScreenDraw( Picture source,Picture dest, //Place the upper-left corner// of the source image at the // following location in the// destination image. int destX,int destY){ int width = source.getWidth();int height = source.getHeight(); Pixel pixel = null;Color color = null; for(int row = 0;row<height;row++){ for(int col = 0;col<width;col++){ color = source.getPixel(col,row).getColor();if(!(color.equals(Color.GREEN))){ pixel = dest.getPixel(destX + col,destY + row);pixel.setColor(color); }//end if}//end inner loop }//end outer loop}//end greenScreenDraw //----------------------------------------------------////Crops a Picture object to the given width and height // with the upper-left corner located at startCol and// startRow. private Picture crop(Picture pic,int startCol,int startRow, int width,int height){ Picture output = new Picture(width,height);int colOut = 0; int rowOut = 0;int col = 0; int row = 0;Pixel pixel = null; Color color = null;for(col = startCol;col<startCol+width;col++){ for(row = startRow;row<startRow+height;row++){ color = pic.getPixel(col,row).getColor();pixel = output.getPixel(colOut,rowOut); pixel.setColor(color);rowOut++; }//end inner looprowOut = 0; colOut++;}//end outer loop return output;}//end crop }//end class Prob04Runner

-end-

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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Can you compute that for me. Ty
Jude
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David
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what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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Pedro
A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
Sahid Reply
you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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Maurice Reply
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Maurice
answer
Magreth
progressive wave
Magreth
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Mohammed
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Who can show me the full solution in this problem?
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Source:  OpenStax, Object-oriented programming (oop) with java. OpenStax CNX. Jun 29, 2016 Download for free at https://legacy.cnx.org/content/col11441/1.201
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