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Npr05_17

% file npr05_17.m % Data for problem P5-17PG1 = 84/150; PG2 = 66/125;A = [0.61 0.31 0.08      0.50 0.38 0.12     0.23 0.64 0.13      0.29 0.63 0.08     0.32 0.62 0.06      0.58 0.23 0.19     0.19 0.70 0.11      0.56 0.38 0.06     0.65 0.20 0.15      0.29 0.63 0.08]; B = [0.41 0.51 0.08     0.29 0.65 0.06      0.59 0.33 0.08     0.57 0.29 0.14      0.42 0.50 0.08     0.29 0.62 0.09      0.56 0.32 0.12     0.29 0.64 0.08      0.41 0.50 0.09     0.59 0.32 0.09];disp('Call for oddsdp')

Npr06_10

% file npr06_10.m % Data for problem P6-10pm = [ 0.072 0.048 0.018 0.012 0.168 0.112 0.042 0.028 ...        0.062 0.048 0.028 0.010 0.170 0.110 0.040 0.032]; c  = [-5.3 -2.5 2.3 4.2 -3.7]; disp('Minterm probabilities are in pm, coefficients in c')

Npr06_12

% file npr06_12.m % Data for problem P6-12pm = 0.001*[5 7 6 8 9 14 22 33 21 32 50 75 86 129 201 302]; c = [1 1 1 1 0]; disp('Minterm probabilities in pm, coefficients in c')

Npr06_18.m

% file npr06_18.m % Data for problem P6-18cx = [5 17 21 8 15 0];cy = [8 15 12 18 15 12 0];pmx = minprob(0.01*[37 22 38 81 63]);pmy = minprob(0.01*[77 52 23 41 83 58]);disp('Data in cx, cy, pmx, pmy')

Npr07_01

\begin{verbatim} % file npr07_01.m% Data for problem P7-1 T = [1 3 2 3 4 2 1 3 5 2]; pc = 0.01*[ 8 13 6 9 14 11 12 7 11 9]; disp('Data are in T and pc')\end{verbatim}

Npr07_02

% file npr07_02.m % Data for problem P7-2T = [3.5 5.0 3.5 7.5 5.0 5.0 3.5 7.5];pc = 0.01*[10 15 15 20 10 5 10 15];disp('Data are in T, pc')

Npr08_01

% file npr08_01.m % Solution for problem P8-1X = 0:2; Y = 0:2;Pn = [132  24   0; 864 144  6; 1260 216 6];P = Pn/(52*51); disp('Data in Pn, P, X, Y')

Npr08_02

% file npr08_02.m % Solution for problem P8-2X = 0:2; Y = 0:2;Pn = [6 0 0; 18 12 0; 6 12 2];P = Pn/56; disp('Data are in X, Y,Pn, P')

Npr08_03

% file npr08_03.m % Solution for problem  P8-3X = 1:6; Y = 0:6;P0 = zeros(6,7);       % Initialize for i = 1:6            % Calculate rows of Y probabilities    P0(i,1:i+1) = (1/6)*ibinom(i,1/2,0:i); endP = rot90(P0);         % Rotate to orient as on the plane PY = fliplr(sum(P'));  % Reverse to put in normal orderdisp('Answers are in X, Y, P, PY')

Npr08_04

% file npr08_04.m % Solution for problem P8-4X = 2:12; Y = 0:12;PX = (1/36)*[1 2 3 4 5 6 5 4 3 2 1];P0 = zeros(11,13); for i = 1:11    P0(i,1:i+2) = PX(i)*ibinom(i+1,1/2,0:i+1); endP = rot90(P0); PY = fliplr(sum(P'));disp('Answers are in X, Y, PY, P')

Npr08_05

% file npr08_05.m % Data and basic calculations for P8-5PX = (1/36)*[1 2 3 4 5 6 5 4 3 2 1];X = 2:12; Y = 0:12;P0 = zeros(11,13); for i = 1:11  P0(i,1:i+2) = PX(i)*ibinom(i+1,1/6,0:i+1); endP = rot90(P0); PY = fliplr(sum(P'));disp('Answers are in X, Y, P, PY')

Npr08_06

% file  Newprobs/pr08_06.m % Data for problem P8-6 (from Exam 2, 95f)P = [0.0483    0.0357    0.0420    0.0399    0.0441      0.0437    0.0323    0.0380    0.0361    0.0399     0.0713    0.0527    0.0620    0.0609    0.0551      0.0667    0.0493    0.0580    0.0651    0.0589]; X = [-2.3 -0.7 1.1 3.9 5.1]; Y = [ 1.3  2.5 4.1 5.3]; disp('Data are in X, Y, P')

Npr08_07

% file pr08_07.m  (from Exam3, 96s) % Data for problem P8-7X = [-3.1 -0.5  1.2  2.4  3.7 4.9];Y = [-3.8 -2.0  4.1  7.5];P = [ 0.0090    0.0396    0.0594    0.0216    0.0440    0.0203;       0.0495         0    0.1089    0.0528    0.0363    0.0231;      0.0405    0.1320    0.0891    0.0324    0.0297    0.0189;       0.0510    0.0484    0.0726    0.0132         0    0.0077]; disp('Data are in X, Y, P')

Npr08_08

% file Newprobs/pr08_08.m (from Exam 4 96s) % Data for problem P8-8P = [0.0156  0.0191  0.0081  0.0035  0.0091  0.0070  0.0098  0.0056  0.0091  0.0049;      0.0064  0.0204  0.0108  0.0040  0.0054  0.0080  0.0112  0.0064  0.0104  0.0056;     0.0196  0.0256  0.0126  0.0060  0.0156  0.0120  0.0168  0.0096  0.0056  0.0084;      0.0112  0.0182  0.0108  0.0070  0.0182  0.0140  0.0196  0.0012  0.0182  0.0038;     0.0060  0.0260  0.0162  0.0050  0.0160  0.0200  0.0280  0.0060  0.0160  0.0040;      0.0096  0.0056  0.0072  0.0060  0.0256  0.0120  0.0268  0.0096  0.0256  0.0084;     0.0044  0.0134  0.0180  0.0140  0.0234  0.0180  0.0252  0.0244  0.0234  0.0126;      0.0072  0.0017  0.0063  0.0045  0.0167  0.0090  0.0026  0.0172  0.0217  0.0223];  X = 1:2:19; Y = [-5  -3  -1  3  5 9 10 12]; disp('Data are in X, Y, P')

Npr08_09

% file pr08_09.m   (from Exam3 95f) % Data for problem P8-9P = [0.0390    0.0110    0.0050    0.0010    0.0010;      0.0650    0.0700    0.0500    0.0150    0.0100;     0.0310    0.0610    0.1370    0.0510    0.0330;      0.0120    0.0490    0.1630    0.0580    0.0390;     0.0030    0.0090    0.0450    0.0250    0.0170];X = [1 1.5 2 2.5 3];Y = [1 2 3 4 5];disp('Data are in X, Y, P')

Npr09_02

\begin{verbatim} % file Newprobs/npr09_02.m% Data for problem P9-2 P = [0.0589 0.0342 0.0304 0.0456 0.0209;0.0961 0.0556 0.0498 0.0744 0.0341; 0.0682 0.0398 0.0350 0.0528 0.0242;0.0868 0.0504 0.0448 0.0672 0.0308];X = [-3.9 -1.7 1.5 2.8 4.1];Y = [-2 1 2.6 5.1];disp('Data are in X, Y, P') \end{verbatim}

Npr10_16

\begin{verbatim} % file npr10_16.m% Data for problem P10-16 cx = [-2 1 3 0]; pmx = 0.001*[255 25 375 45 108 12 162 18]; cy = [1 3 1 -3]; pmy = minprob(0.01*[32 56 40]); Z = [-1.3 1.2 2.7 3.4 5.8]; PZ = 0.01*[12 24 43 13 8]; disp('Data are in cx, pmx, cy, pmy, Z, PZ')\end{verbatim}

Npr12_10

% file npr12_10.m % Data for problems P12-10, P12_11cx = [-3.3 -1.7 2.3 7.6 -3.4];pmx = 0.0001*[475 725 120 180 1125 1675 280 420 480 720 130 170 1120 1680 270 430];cy = [10 17 20 -10];pmy = 0.01*[6 14 9 21 6 14 9 21];disp('Data are in cx, cy, pmx and pmy')

Npr16_07

\begin{verbatim} % file npr16_07.m% Transition matrix for problem P16-7 P = [0.23 0.32 0.02 0.22 0.21;0.29 0.41 0.10 0.08 0.12; 0.22 0.07 0.31 0.14 0.26;0.32 0.15 0.05 0.33 0.15; 0.08 0.23 0.31 0.09 0.29]; disp('Transition matrix is P')\end{verbatim}

Npr16_09

% file npr16_09.m % Transition matrix for problem P16-9P = [0.2 0.5 0.3  0   0   0   0;      0.6 0.1 0.3  0   0   0   0;     0.2 0.7 0.1  0   0   0   0;      0   0   0  0.6 0.4  0   0;       0   0   0  0.5 0.5  0   0;     0.1 0.3  0  0.2 0.1 0.1 0.2;      0.1 0.2 0.1 0.2 0.2 0.2  0 ]; disp('Transition matrix is P')

Questions & Answers

Application of nanotechnology in medicine
what is variations in raman spectra for nanomaterials
Jyoti Reply
I only see partial conversation and what's the question here!
Crow Reply
what about nanotechnology for water purification
RAW Reply
please someone correct me if I'm wrong but I think one can use nanoparticles, specially silver nanoparticles for water treatment.
Damian
yes that's correct
Professor
I think
Professor
what is the stm
Brian Reply
is there industrial application of fullrenes. What is the method to prepare fullrene on large scale.?
Rafiq
industrial application...? mmm I think on the medical side as drug carrier, but you should go deeper on your research, I may be wrong
Damian
How we are making nano material?
LITNING Reply
what is a peer
LITNING Reply
What is meant by 'nano scale'?
LITNING Reply
What is STMs full form?
LITNING
scanning tunneling microscope
Sahil
how nano science is used for hydrophobicity
Santosh
Do u think that Graphene and Fullrene fiber can be used to make Air Plane body structure the lightest and strongest. Rafiq
Rafiq
what is differents between GO and RGO?
Mahi
what is simplest way to understand the applications of nano robots used to detect the cancer affected cell of human body.? How this robot is carried to required site of body cell.? what will be the carrier material and how can be detected that correct delivery of drug is done Rafiq
Rafiq
if virus is killing to make ARTIFICIAL DNA OF GRAPHENE FOR KILLED THE VIRUS .THIS IS OUR ASSUMPTION
Anam
analytical skills graphene is prepared to kill any type viruses .
Anam
what is Nano technology ?
Bob Reply
write examples of Nano molecule?
Bob
The nanotechnology is as new science, to scale nanometric
brayan
nanotechnology is the study, desing, synthesis, manipulation and application of materials and functional systems through control of matter at nanoscale
Damian
Is there any normative that regulates the use of silver nanoparticles?
Damian Reply
what king of growth are you checking .?
Renato
What fields keep nano created devices from performing or assimulating ? Magnetic fields ? Are do they assimilate ?
Stoney Reply
why we need to study biomolecules, molecular biology in nanotechnology?
Adin Reply
?
Kyle
yes I'm doing my masters in nanotechnology, we are being studying all these domains as well..
Adin
why?
Adin
what school?
Kyle
biomolecules are e building blocks of every organics and inorganic materials.
Joe
anyone know any internet site where one can find nanotechnology papers?
Damian Reply
research.net
kanaga
sciencedirect big data base
Ernesto
Introduction about quantum dots in nanotechnology
Praveena Reply
hi
Loga
what does nano mean?
Anassong Reply
nano basically means 10^(-9). nanometer is a unit to measure length.
Bharti
how did you get the value of 2000N.What calculations are needed to arrive at it
Smarajit Reply
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Good
A fair die is tossed 180 times. Find the probability P that the face 6 will appear between 29 and 32 times inclusive
Samson Reply

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Source:  OpenStax, Applied probability. OpenStax CNX. Aug 31, 2009 Download for free at http://cnx.org/content/col10708/1.6
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