# 2.13 Breuke - gemengde bewerkings

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## Memorandum

24.1 ( )

or

÷

x

+

_

• (i) = $\frac{7}{2}$ x $\frac{\text{30}}{7}$ - 10

= $\frac{\text{210}}{\text{14}}$ - 10

= 15 – 10

s = 5

1. = 32 - 11 $\frac{3}{4}$

v = 20 $\frac{1}{4}$

1. = $\frac{\text{23}}{4}$ x $\frac{4}{7}$

= $\frac{\text{23}}{7}$

p = 3 $\frac{2}{7}$

26. a) Metode: Kanselleer uit

Antwoord: $\frac{1}{8}$

b) $\frac{1}{\text{25}}$

## Aktiwiteit: gemengde bewerkings [lu 1.10]

24. GEMENGDE BEWERKINGS

24.1 Onthou jy nog?

• Skryf gou die volgorde van bewerkings hier neer:

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24.2 Pas dit nou toe in die volgende:

(i) $s=3\frac{1}{2}×4\frac{2}{7}-\frac{2}{3}\text{of}\text{15}$

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(ii) $v=\frac{1}{2}\text{of}\text{64}-\left(7\frac{1}{2}+4\frac{1}{4}\right)$

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(iii) $p=5\frac{3}{4}÷\left(3\frac{1}{8}-1\frac{3}{4}\right)$

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25. Tyd vir selfassessering

26. KOPKRAPPERS!

a) Wat sal die antwoord van die volgende wees? Probeer dit kry sonder ellelange bewerkings!

$o=\left(1-\frac{1}{2}\right)×\left(1-\frac{1}{3}\right)×\left(1-\frac{1}{4}\right)×\left(1-\frac{1}{5}\right)×\left(1-\frac{1}{6}\right)×\left(1-\frac{1}{7}\right)×\left(1-\frac{1}{8}\right)$

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b) As jy so sou aanhou met die patroon tot by . . . $\left(1-\frac{1}{\text{25}}\right)$ , wat sal die antwoord dan wees?

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## Assessering

Leeruitkomste 1: Die leerder is in staat om getalle en die verwantskappe daarvan te herken, te beskryf en voor te stel, en om tydens probleemoplossing bevoeg en met selfvertroue te tel, te skat, te bereken en te kontroleer.

Assesseringstandaard 1.10: Dit is duidelik wanneer die leerder ‘n verskeidenheid strategieë gebruik om oplossings te kontroleer en die redelikheid daarvan te beoordeel.

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