# 0.1 Analyzing chemical equations

 Page 1 / 3

Application of mole concept requires a balanced chemical equation. The different constituents of the reaction – reactants and products – bear a simple whole number proportion same as the proportion of the coefficients associated with constituents. According to mole concept, the molar mass of constituents participates in this proportion. For a generic consideration as given :

$xA+yB\to {A}_{x}{B}_{y}$

Here, 1 mole of compound ( ${A}_{x}{B}_{y}$ ) involves x mole of A and y mole of B. Using symbols :

$\text{x moles of A}\equiv \text{y moles of B}\equiv \text{1 mole of}{A}_{x}{B}_{y}$

The point to emphasize here is that this is a relation, which is connected by "equivalence sign (≡)" - not by "equal to (=)" sign. We know that 2 moles of hydrogen reacts with 1 mole of oxygen to form 2 moles of water. Clearly, we can not equate like 2=1=2. We need to apply unitary method to interpret this relation of equivalence. We say that since x moles of A react with y moles of B. Hence, 1 mole of A reacts with y/x moles of "B". Similarly, 1 mole of B reacts with x/y moles of "A". Once we know the correspondence for 1 mole, we can find correspondence for any other value of participating moles of either A or B.

## Mass of participating entities in a reaction

Mole concept is used to calculate mass of individual constituent of a chemical reaction. The proportion of molar mass is converted to determine proportion of mass in which entities are involved in a reaction. The symbolic mass relation for the chemical reaction as given above is :

$x{M}_{A}\phantom{\rule{2pt}{0ex}}\text{gm of A}\equiv y{M}_{B}\phantom{\rule{2pt}{0ex}}\text{gm of B}\equiv {M}_{{A}_{x}{B}_{y}}\phantom{\rule{2pt}{0ex}}\text{gm of}{A}_{x}{B}_{y}$

We apply unitary method on the mass relation related with equivalent sign (≡) to determine mass of different entities of the reaction.

Problem : Calculate mass of lime (CaO) that can be prepared by heating 500 kg of 90 % pure limestone ( $CaC{O}_{3}$ .

Solution : Purity of CaCO3 is 90 %. Hence,

$\text{Mass of}\phantom{\rule{1em}{0ex}}CaC{O}_{3}=0.9X500=450\phantom{\rule{1em}{0ex}}kg$

The chemical reaction involved here is :

$CaC{O}_{3}\to CaO+C{O}_{2}$

Applying mole concept :

$⇒\text{1 mole of}\phantom{\rule{1em}{0ex}}CaC{O}_{3}\equiv \text{1 mole of CaO}$

$⇒\text{(40 + 12 + 3X 16) gm of}\phantom{\rule{1em}{0ex}}CaC{O}_{3}\equiv \text{(40 + 16) gm of CaO}$

$⇒\text{100 gm of}\phantom{\rule{1em}{0ex}}CaC{O}_{3}\equiv \text{56 gm of CaO}$

$⇒\text{100 kg of}\phantom{\rule{1em}{0ex}}CaC{O}_{3}\equiv \text{56 kg of CaO}$

Applying unitary method :

$⇒\text{mass of CaO produced}=\frac{56X450}{100}=252\phantom{\rule{1em}{0ex}}kg$

Problem : Igniting $Mn{O}_{2}$ converts it quantitatively to $M{n}_{3}{O}_{4}$ . A sample of pyrolusite contains 80% $Mn{O}_{2}$ , 15 % $Si{O}_{2}$ and 5 % water. The sample is ignited in air to constant weight. What is the percentage of manganese in the ignited sample ? ( ${A}_{Mn}=55$ )

Solution : The sample contains three components. Since this question involves percentage, we shall consider a sample of 100 gm. Water component weighing 5 gm evaporates on ignition. $Si{O}_{2}$ weighing 15 gm does not change. On the other hand, 80 gm of $Mn{O}_{2}$ converts as :

$3Mn{O}_{2}\to M{n}_{3}{O}_{4}+{O}_{2}$

Applying mole concept,

$\text{3 moles of}Mn{O}_{2}\equiv \text{1 mole of}M{n}_{3}{O}_{4}$

$3X\left(55+2X16\right)\text{gm of}Mn{O}_{2}\equiv 1X\left(3X55+4X16\right)\text{gm of}M{n}_{3}{O}_{4}$

$261\text{gm of}Mn{O}_{2}\equiv 229\text{gm of}M{n}_{3}{O}_{4}$

Since sample is ignited in air to constant weight, it means that all of $\mathrm{Mn}{O}_{2}$ in the sample is converted. Using unitary method, we determine mass of converted mass of $M{n}_{3}{O}_{4}$ for 80 gm of $\mathrm{Mn}{O}_{2}$ :

$\text{Mass of}M{n}_{3}{O}_{4}\text{on conversion}=\frac{229}{261}X80=70.2\phantom{\rule{1em}{0ex}}gm$

We are required to find the percentage of Mn in the ignited sample. Thus, we need to determine the mass of the ignited sample. The ignited sample contains 70.2 gm of $M{n}_{3}{O}_{4}$ and 15 gm of $Si{O}_{2}$ . Total mass of ignited sample is 70.2+15 = 85.4 gm. On the other hand, amount of Mn in $M{n}_{3}{O}_{4}$ is calculated from its molecular constitution :

$229\text{gm of}M{n}_{3}{O}_{4}\equiv 3X55\text{gm of Mn}\equiv 165\text{gm of Mn}$

$\text{Amount of Mn in 70.2 gm of}M{n}_{3}{O}_{4}=\frac{165}{229}X70.2=0.72X70.2=50.54\phantom{\rule{1em}{0ex}}gm$

Clearly, 85.4 gm of ignited sample contains 50.54 gm of Mn. Hence,

$\text{Percentage amount of manganese in the ignited sample}=\frac{50.54}{85.4}X100=59.2%$

where we get a research paper on Nano chemistry....?
what are the products of Nano chemistry?
There are lots of products of nano chemistry... Like nano coatings.....carbon fiber.. And lots of others..
learn
Even nanotechnology is pretty much all about chemistry... Its the chemistry on quantum or atomic level
learn
da
no nanotechnology is also a part of physics and maths it requires angle formulas and some pressure regarding concepts
Bhagvanji
Preparation and Applications of Nanomaterial for Drug Delivery
revolt
da
Application of nanotechnology in medicine
what is variations in raman spectra for nanomaterials
I only see partial conversation and what's the question here!
what about nanotechnology for water purification
please someone correct me if I'm wrong but I think one can use nanoparticles, specially silver nanoparticles for water treatment.
Damian
yes that's correct
Professor
I think
Professor
Nasa has use it in the 60's, copper as water purification in the moon travel.
Alexandre
nanocopper obvius
Alexandre
what is the stm
is there industrial application of fullrenes. What is the method to prepare fullrene on large scale.?
Rafiq
industrial application...? mmm I think on the medical side as drug carrier, but you should go deeper on your research, I may be wrong
Damian
How we are making nano material?
what is a peer
What is meant by 'nano scale'?
What is STMs full form?
LITNING
scanning tunneling microscope
Sahil
how nano science is used for hydrophobicity
Santosh
Do u think that Graphene and Fullrene fiber can be used to make Air Plane body structure the lightest and strongest. Rafiq
Rafiq
what is differents between GO and RGO?
Mahi
what is simplest way to understand the applications of nano robots used to detect the cancer affected cell of human body.? How this robot is carried to required site of body cell.? what will be the carrier material and how can be detected that correct delivery of drug is done Rafiq
Rafiq
if virus is killing to make ARTIFICIAL DNA OF GRAPHENE FOR KILLED THE VIRUS .THIS IS OUR ASSUMPTION
Anam
analytical skills graphene is prepared to kill any type viruses .
Anam
Any one who tell me about Preparation and application of Nanomaterial for drug Delivery
Hafiz
what is Nano technology ?
write examples of Nano molecule?
Bob
The nanotechnology is as new science, to scale nanometric
brayan
nanotechnology is the study, desing, synthesis, manipulation and application of materials and functional systems through control of matter at nanoscale
Damian
Is there any normative that regulates the use of silver nanoparticles?
what king of growth are you checking .?
Renato
What fields keep nano created devices from performing or assimulating ? Magnetic fields ? Are do they assimilate ?
why we need to study biomolecules, molecular biology in nanotechnology?
?
Kyle
yes I'm doing my masters in nanotechnology, we are being studying all these domains as well..
why?
what school?
Kyle
biomolecules are e building blocks of every organics and inorganic materials.
Joe
Got questions? Join the online conversation and get instant answers! By Rhodes By JavaChamp Team By Yacoub Jayoghli By Joli Julianna By OpenStax By OpenStax By OpenStax By Janet Forrester By Madison Christian By JavaChamp Team