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This program performs each of the processes listed above. However, it does not perform those processes in the special order used by an FFT algorithm thatcauses the FFT algorithm to be able to perform those processes at very high speed.

How the processes are implemented

The decomposition process in this program takes the complex samples in the order that they appear in the input complex series. The transform of eachcomplex sample is simply the sample itself. This is the result that would be obtained by actually computing the transform of the complex sample if the samplewere the first sample in the series.

The transform result for each complex sample (the sample itself) is then corrected for position by applying sine and cosine curves to reflect the actual position of the complex sample within the original complex series.

In order to accomplish the recombination of the corrected transform results, the real and imaginary parts of the correctedtransform are added to accumulators. These accumulators are used to accumulate the corrected real and imaginary parts from the corrected transforms for all ofthe individual complex samples.

Once the real and imaginary parts have been accumulated for all of the complex samples, the real part of the accumulatorrepresents the real part of the transform of the original complex series. The imaginary part of the accumulator represents the imaginary part of the transformof the original complex series. However, an actual transform was never performed on the original complex series.

Three cases are examined

This program creates three separate complex series, applies the processes listed above to each of those series, and displaysthe results on the screen.

No attempt is made to manage the decomposition and the subsequent recombination in the manner of a true FFT algorithm. Therefore, this program isdesigned to illustrate the processes involved, and is not designed to provide the speed of a true FFT algorithm.

This program was tested using JDK 1.8 under Windows 7.

Will discuss in fragments

As is my usual approach, I will discuss and explain this program in fragments. A complete listing of the program is provided in Listing 9 near the end of the module.

The program named Fft02

The program begins in Listing 1 , which shows the beginning of the controlling class named Fft02 and the beginning of the main method.

Listing 1. Beginning of the program named Fft02?
class Fft02{ public static void main(String[]args){ Transform transform = new Transform();

Instantiate a Transform object

The first statement in the main method instantiates an object of the Transform class. This object implements the processes used in an FFT, but does not implement those processes in the special order required by an FFT algorithm.

The purpose of an object of the Transform class is to illustrate the processes commonly used in an FFT in a manner that is more easily understoodthan is often the case with an actual FFT algorithm.

I will put the main method on the back burner for the moment and explain the class named Transform .

Questions & Answers

how did you get 1640
Noor Reply
If auger is pair are the roots of equation x2+5x-3=0
Peter Reply
Wayne and Dennis like to ride the bike path from Riverside Park to the beach. Dennis’s speed is seven miles per hour faster than Wayne’s speed, so it takes Wayne 2 hours to ride to the beach while it takes Dennis 1.5 hours for the ride. Find the speed of both bikers.
MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
George
Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
Salma
Devon is 32 32​​ years older than his son, Milan. The sum of both their ages is 54 54​. Using the variables d d​ and m m​ to represent the ages of Devon and Milan, respectively, write a system of equations to describe this situation. Enter the equations below, separated by a comma.
Aaron Reply
find product (-6m+6) ( 3m²+4m-3)
SIMRAN Reply
-42m²+60m-18
Salma
what is the solution
bill
how did you arrive at this answer?
bill
-24m+3+3mÁ^2
Susan
i really want to learn
Amira
I only got 42 the rest i don't know how to solve it. Please i need help from anyone to help me improve my solving mathematics please
Amira
Hw did u arrive to this answer.
Aphelele
hi
Bajemah
-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
Salma
complete the table of valuesfor each given equatio then graph. 1.x+2y=3
Jovelyn Reply
x=3-2y
Salma
y=x+3/2
Salma
Hi
Enock
given that (7x-5):(2+4x)=8:7find the value of x
Nandala
3x-12y=18
Kelvin
please why isn't that the 0is in ten thousand place
Grace Reply
please why is it that the 0is in the place of ten thousand
Grace
Send the example to me here and let me see
Stephen
A meditation garden is in the shape of a right triangle, with one leg 7 feet. The length of the hypotenuse is one more than the length of one of the other legs. Find the lengths of the hypotenuse and the other leg
Marry Reply
how far
Abubakar
cool u
Enock
state in which quadrant or on which axis each of the following angles given measure. in standard position would lie 89°
Abegail Reply
hello
BenJay
hi
Method
I am eliacin, I need your help in maths
Rood
how can I help
Sir
hmm can we speak here?
Amoon
however, may I ask you some questions about Algarba?
Amoon
hi
Enock
what the last part of the problem mean?
Roger
The Jones family took a 15 mile canoe ride down the Indian River in three hours. After lunch, the return trip back up the river took five hours. Find the rate, in mph, of the canoe in still water and the rate of the current.
cameron Reply
Shakir works at a computer store. His weekly pay will be either a fixed amount, $925, or $500 plus 12% of his total sales. How much should his total sales be for his variable pay option to exceed the fixed amount of $925.
mahnoor Reply
I'm guessing, but it's somewhere around $4335.00 I think
Lewis
12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
Munster
difference between rational and irrational numbers
Arundhati Reply
When traveling to Great Britain, Bethany exchanged $602 US dollars into £515 British pounds. How many pounds did she receive for each US dollar?
Jakoiya Reply
how to reduced echelon form
Solomon Reply
Jazmine trained for 3 hours on Saturday. She ran 8 miles and then biked 24 miles. Her biking speed is 4 mph faster than her running speed. What is her running speed?
Zack Reply
d=r×t the equation would be 8/r+24/r+4=3 worked out
Sheirtina
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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