<< Chapter < Page Chapter >> Page >
This module describes the continuous time Fourier Series (CTFS). It is based on the following modules:Fourier Series: Eigenfunction Approach at http://cnx.org/content/m10496/latest/ by Justin Romberg, Derivation of Fourier Coefficients Equation at http://cnx.org/content/m10733/latest/ by Michael Haag,Fourier Series and LTI Systems at http://cnx.org/content/m10752/latest/ by Justin Romberg, and Fourier Series Wrap-Up at http://cnx.org/content/m10749/latest/ by Michael Haag and Justin Romberg.

Introduction

In this module, we will derive an expansion for continuous-time, periodic functions, and in doing so, derive the Continuous Time Fourier Series (CTFS).

Since complex exponentials are eigenfunctions of linear time-invariant (LTI) systems , calculating the output of an LTI system given s t as an input amounts to simple multiplication, where H s is the eigenvalue corresponding to s. As shown in the figure, a simple exponential input would yield the output

y t H s s t

Simple LTI system.

Using this and the fact that is linear, calculating y t for combinations of complex exponentials is also straightforward.

c 1 s 1 t c 2 s 2 t c 1 H s 1 s 1 t c 2 H s 2 s 2 t n c n s n t n c n H s n s n t

The action of H on an input such as those in the two equations above is easy to explain. independently scales each exponential component s n t by a different complex number H s n . As such, if we can write a function f t as a combination of complex exponentials it allows us to easily calculate the output of a system.

Fourier series synthesis

Joseph Fourier demonstrated that an arbitrary f t can be written as a linear combination of harmonic complex sinusoids

f t n c n j ω 0 n t
where ω 0 2 T is the fundamental frequency. For almost all f t of practical interest, there exists c n to make [link] true. If f t is finite energy ( f t L 0 T 2 ), then the equality in [link] holds in the sense of energy convergence; if f t is continuous, then [link] holds pointwise. Also, if f t meets some mild conditions (the Dirichlet conditions), then [link] holds pointwise everywhere except at points of discontinuity.

The c n - called the Fourier coefficients - tell us "how much" of the sinusoid j ω 0 n t is in f t . The formula shows f t as a sum of complex exponentials, each of which is easily processed by an LTI system (since it is an eigenfunction of every LTI system). Mathematically, it tells us that the set ofcomplex exponentials n n j ω 0 n t form a basis for the space of T-periodic continuous time functions.

We know from Euler's formula that cos ( ω t ) + sin ( ω t ) = 1 - j 2 e j ω t + 1 + j 2 e - j ω t .

Got questions? Get instant answers now!

Synthesis with sinusoids demonstration

timeshiftDemo
Interact(when online) with a Mathematica CDF demonstrating sinusoid synthesis. To download, right click and save as .cdf.

Guitar oscillations on an iphone

Fourier series analysis

Finding the coefficients of the Fourier series expansion involves some algebraic manipulation of the synthesis formula. First of all we will multiply both sides of the equation by j ω 0 k t , where k .

f t j ω 0 k t n c n j ω 0 n t j ω 0 k t
Now integrate both sides over a given period, T :
t T 0 f t j ω 0 k t t T 0 n c n j ω 0 n t j ω 0 k t
On the right-hand side we can switch the summation andintegral and factor the constant out of the integral.
t T 0 f t j ω 0 k t n c n t T 0 j ω 0 n k t
Now that we have made this seemingly more complicated, let us focus on just the integral, t T 0 j ω 0 n k t , on the right-hand side of the above equation. For this integral we will need to consider two cases: n k and n k . For n k we will have:
n n k t T 0 j ω 0 n k t T
For n k , we will have:
n n k t T 0 j ω 0 n k t t T 0 ω 0 n k t j t T 0 ω 0 n k t
But ω 0 n k t has an integer number of periods, n k , between 0 and T . Imagine a graph of the cosine; because it has an integer number of periods, there areequal areas above and below the x-axis of the graph. This statement holds true for ω 0 n k t as well. What this means is
t T 0 ω 0 n k t 0
which also holds for the integral involving the sine function. Therefore, we conclude the following about our integral ofinterest:
t T 0 j ω 0 n k t T n k 0
Now let us return our attention to our complicated equation, [link] , to see if we can finish finding an equation for our Fourier coefficients. Using thefacts that we have just proven above, we can see that the only time [link] will have a nonzero result is when k and n are equal:
n n k t T 0 f t j ω 0 n t T c n
Finally, we have our general equation for the Fourier coefficients:
c n 1 T t T 0 f t j ω 0 n t

Consider the square wave function given by

x ( t ) = 1 / 2 t 1 / 2 - 1 / 2 t > 1 / 2

on the unit interval t Z [ 0 , 1 ) .

c k = 0 1 x ( t ) e - j 2 π k t d t = 0 1 / 2 1 2 e - j 2 π k t d t - 1 / 2 1 1 2 e - j 2 π k t d t = j - 1 + e j π k 2 π k

Thus, the Fourier coefficients of this function found using the Fourier series analysis formula are

c k = - j / π k k odd 0 k even .
Got questions? Get instant answers now!

Fourier series summary

Because complex exponentials are eigenfunctions of LTI systems, it is often useful to represent signals using a set of complex exponentials as a basis. The continuous time Fourier series synthesis formula expresses a continuous time, periodic function as the sum of continuous time, discrete frequency complex exponentials.

f t n c n j ω 0 n t
The continuous time Fourier series analysis formula gives the coefficients of the Fourier series expansion.
c n 1 T t T 0 f t j ω 0 n t
In both of these equations ω 0 2 T is the fundamental frequency.

Questions & Answers

how do you get the 2/50
Abba Reply
number of sport play by 50 student construct discrete data
Aminu Reply
width of the frangebany leaves on how to write a introduction
Theresa Reply
Solve the mean of variance
Veronica Reply
Step 1: Find the mean. To find the mean, add up all the scores, then divide them by the number of scores. ... Step 2: Find each score's deviation from the mean. ... Step 3: Square each deviation from the mean. ... Step 4: Find the sum of squares. ... Step 5: Divide the sum of squares by n – 1 or N.
kenneth
what is error
Yakuba Reply
Is mistake done to something
Vutshila
Hy
anas
hy
What is the life teble
anas
hy
Jibrin
statistics is the analyzing of data
Tajudeen Reply
what is statics?
Zelalem Reply
how do you calculate mean
Gloria Reply
diveving the sum if all values
Shaynaynay
let A1,A2 and A3 events be independent,show that (A1)^c, (A2)^c and (A3)^c are independent?
Fisaye Reply
what is statistics
Akhisani Reply
data collected all over the world
Shaynaynay
construct a less than and more than table
Imad Reply
The sample of 16 students is taken. The average age in the sample was 22 years with astandard deviation of 6 years. Construct a 95% confidence interval for the age of the population.
Aschalew Reply
Bhartdarshan' is an internet-based travel agency wherein customer can see videos of the cities they plant to visit. The number of hits daily is a normally distributed random variable with a mean of 10,000 and a standard deviation of 2,400 a. what is the probability of getting more than 12,000 hits? b. what is the probability of getting fewer than 9,000 hits?
Akshay Reply
Bhartdarshan'is an internet-based travel agency wherein customer can see videos of the cities they plan to visit. The number of hits daily is a normally distributed random variable with a mean of 10,000 and a standard deviation of 2,400. a. What is the probability of getting more than 12,000 hits
Akshay
1
Bright
Sorry i want to learn more about this question
Bright
Someone help
Bright
a= 0.20233 b=0.3384
Sufiyan
a
Shaynaynay
How do I interpret level of significance?
Mohd Reply
It depends on your business problem or in Machine Learning you could use ROC- AUC cruve to decide the threshold value
Shivam
how skewness and kurtosis are used in statistics
Owen Reply
yes what is it
Taneeya
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Signals and systems. OpenStax CNX. Aug 14, 2014 Download for free at http://legacy.cnx.org/content/col10064/1.15
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Signals and systems' conversation and receive update notifications?

Ask