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What we have learned so far

So far, the main things that we have learned is that shorter pulses require greater bandwidth, and the bandwidth required to faithfully represent atruncated sinusoidal pulse is the reciprocal of the length of the pulse.

Separating closely spaced frequencies

Now we will look at the issues involved in using spectral analysis to separate and identify the frequencies of two closely-spaced spectral peaks for apulse composed of the sum of two sinusoids. Once again, we will begin by looking at some results and then discuss the code that produced those results.

Five new pulses

The five pulses that we will be working with in this example are shown in Figure 4 . As you can see, these pulses are a little more ugly than the pulses shown in Figure 1 . As you can also see, as was the case in Figure 1 , each pulse appears to be a shorter or longer version of the other pulses in terms of itswaveform.

Figure 4. Five pulses with two sinusoids each.
missing image

Produced by dsp032a

The plots in Figure 4 were produced by the program named Dsp032a , which I will briefly discuss later. (A complete listing of the program is shown in Listing 11 near the end of the module.) This program creates and displays pulses identical to those processed by the program named Dsp032 , which I will also briefly discuss later. (A complete listing of the program named Dsp32 is presented in Listing 12 .)

Five time series containing pulses

The program creates and displays five separate time series, each 400 samples in length. Each time series contains a pulse and the pulses are differentlengths. As before, each of the pulses shown in Figure 4 is half the length of the pulse below it.

The sum of two sinusoids

Each pulse consists of the sum of two sinusoids at closely spaced frequencies. The frequencies of the two sinusoids for all pulses are the same.

All frequency values are specified as type double as a fraction of the sampling frequency. The frequencies of the two sinusoids areequidistant from a center frequency of 0.0625 times the sampling frequency.

(Recall that 0.0625 was the frequency of the only sinusoid contained in the pulses shown in Figure 1 and processed by the program named Dsp031 .)

The frequencies and pulse lengths

The frequency of one sinusoid is (0.0625 - 2.0/len) times the sampling frequency, where len is the length of the time series containing the pulse. (The value for len is 400 samples in this program.) The frequency of the other sinusoid is (0.0625 + 2.0/len) times the sampling frequency.

The lengths of the five pulses are:

  • 25 samples
  • 50 samples
  • 100 samples
  • 200 samples
  • 400 samples

(Note that Figure 4 has tick marks every 25 samples.)

The program named Dsp032a

The only new code in this program is the code in the constructor that creates the pulses and stores them in the data arrays. This code consists of fiveseparate for loops, one for each pulse. The code for the first for loop, which is typical of the five, is shown in Listing 6 .

Listing 6. New code in the the program named Dsp032a.
public Dsp032a(){//constructor //Create the raw datafor(int x = 0;x<len/16;x++){ data1[x]= amp*Math.cos(2*pi*x*freq1) + amp*Math.cos(2*pi*x*freq2);}//end for loop //... code removed for brevity}//end constructor

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
Aislinn Reply
cm
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance
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Can you compute that for me. Ty
Jude
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what is inorganic
emma
Chemistry is a branch of science that deals with the study of matter,it composition,it structure and the changes it undergoes
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A ball is thrown straight up.it passes a 2.0m high window 7.50 m off the ground on it path up and takes 1.30 s to go past the window.what was the ball initial velocity
Krampah Reply
2. A sled plus passenger with total mass 50 kg is pulled 20 m across the snow (0.20) at constant velocity by a force directed 25° above the horizontal. Calculate (a) the work of the applied force, (b) the work of friction, and (c) the total work.
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you have been hired as an espert witness in a court case involving an automobile accident. the accident involved car A of mass 1500kg which crashed into stationary car B of mass 1100kg. the driver of car A applied his brakes 15 m before he skidded and crashed into car B. after the collision, car A s
Samuel Reply
can someone explain to me, an ignorant high school student, why the trend of the graph doesn't follow the fact that the higher frequency a sound wave is, the more power it is, hence, making me think the phons output would follow this general trend?
Joseph Reply
Nevermind i just realied that the graph is the phons output for a person with normal hearing and not just the phons output of the sound waves power, I should read the entire thing next time
Joseph
Follow up question, does anyone know where I can find a graph that accuretly depicts the actual relative "power" output of sound over its frequency instead of just humans hearing
Joseph
"Generation of electrical energy from sound energy | IEEE Conference Publication | IEEE Xplore" ***ieeexplore.ieee.org/document/7150687?reload=true
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Magreth
progressive wave
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Mujahid
A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string?
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Source:  OpenStax, Digital signal processing - dsp. OpenStax CNX. Jan 06, 2016 Download for free at https://legacy.cnx.org/content/col11642/1.38
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