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The equals method

The equals method is defined in the Object class, and can be overridden in subclasses of Object . It is the responsibility of the author of the subclass to override the method so as to implement thatauthor's concept of "equal" insofar as objects of the class are concerned.

The overridden equals method

The reason that the equals method returned true in this case was that the author of the String class provided an overridden version of the equals method.

The default equals method

If the author of the class does not override the equals method, and the default version of the equals method inherited from Object is called on an object of the class, then according to Sun:

"for any reference values x and y, this method returns true if and only if x and y refer to the same object (x==y has the value true)"

In other words, the default version of the equals method inherited from the class Object provides the same behavior as the == operator when applied to object references.

Back to Question 2

Answer 1

C. Joe Joe false

Explanation 1

The identity operator

This program illustrates the behavior of the == operator (sometimes referred to as the identity operator) when used to compare references to objects.

Two String objects with identical contents

As shown in the following fragment, this program instantiates two objects of the String class containing identical character strings.

class Worker{ void doIt(){char[] anArray = {'J','o','e'};String Str1 = new String(anArray); String Str2 = new String(anArray);

The fact that the two String objects contain identical character strings is confirmed by:

  • Both objects are instantiated using the same array object of type char as input.
  • When the toString representations of the two objects are displayed later, the display of each object produces Joe on thecomputer screen.

Compare object references using identity (==)

The references to the two String objects are compared using the == operator, and the result of that comparison is displayed. This comparison will produceeither true or false. The code to accomplish this comparison is shown in the following fragment.

System.out.println( Str1 + " " + Str2 + " " +(Str1 == Str2));

The statement in the above fragment produces the following display:

Joe Joe false

How can this be false?

We know that the two objects are of the same type ( String ) and that they contain the same character strings. Why does the == operator return false?

Doesn't compare the objects

The answer lies in the fact that the above statement doesn't really compare the two objects at all. Rather, it compares the values stored in the referencevariables referring to the two objects. That is not the same as comparing the objects.

References are not equal

Even though the objects are of the same type and contain the same character string, they are two different objects, located in different parts of memory.Therefore, the contents of the two reference variables containing references to the two objects are not equal.

The correct answer is false

The == operator returns false as it should. The only way that the == operator could return true is if both reference variables refer to the same object, (which is not the case) .

The bottom line is ...

The == operator cannot be used to compare two objects for equality. However, it can be used to determine if two reference variables refer to the same object.

Back to Question 1

-end-

Questions & Answers

A golfer on a fairway is 70 m away from the green, which sits below the level of the fairway by 20 m. If the golfer hits the ball at an angle of 40° with an initial speed of 20 m/s, how close to the green does she come?
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Can you compute that for me. Ty
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Source:  OpenStax, Object-oriented programming (oop) with java. OpenStax CNX. Jun 29, 2016 Download for free at https://legacy.cnx.org/content/col11441/1.201
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