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Natuurwetenskappe

Graad 8

Energie: elektrisiteit, energie, warmte en lig

Module 9

Elektrisiteitseenhede

Aktiwiteit:

Om elektrisiteitskoste te bereken

[lu 1.3, 2.4]

  • Ons weet nou dat elektrisiteit verkoop word in die eenheid kilowatt per uur – kWh.

1 kWh IS DIE HOEVEELHEID ELEKTRIESE ENERGIE WAT ‘N TOESTEL MET ‘N DRYWING VAN 1 kW IN EEN UUR GEBRUIK.

Om kWh te bereken, moet ons net die volgende formule gebruik:

kWh = drywing x tyd

Sê nou jy wil weet hoeveel energie jou haardroër (1 500W) in 20 minute gebruik.

kWh = drywing x tyd

= 1 500w x 0.333

= 0.5 kWh

Om die koste van die gebruik van ‘n elektriese toestel uit te werk, gebruik jy die volgende formule:

Koste = elektriese energie in kWh x koste van 1 kWh

As 1 kWh 50c kos, sal jou haardroër se gebruik die volgende koste meebring:

Koste = 0.5 kWh x 50c

= 25c

Opdrag 1:

Kyk na die prentjies en bereken die koste van elke toestel. Gestel elektrisiteit kos R2,50 per kWh.

Gloeilamp brand: 100 W vir 5 ure

TV aan: 80 W vir 5 ure

Yster aan: 1500 W vir 2 ure

Assessering

LU 1

Wetenskaplike Ondersoek Die leerder is in staat om met selfvertroue op weetgierigheid oor natuurlike verskynsels te reageer, en om binne die konteks van wetenskap, tegnologie en die omgewing verbande te ondersoek en probleme op te los.

Dit word bewys as die leerder:

1.1 ondersoeke kan beplan;

1.2 ondersoeke kan uitvoer en data kan insamel;

1.3 data kan evalueer en bevindinge kan kommunikeer.

LU 2

Wetenskaplike KennisDie leerder ken, interpreteer en pas wetenskaplike, tegnologiese en omgewingskennis toe.

Dit word bewys as die leerder:

2.1 sinvolle inligting kan oproep;

2.2 inligting in kategorieë kan plaas;

2.3 inligting kan interpreteer;

2.4 kennis kan toepas.

LU 3

Wetenskap, Omgewing en die GemeenskapDie leerder is in staat om begrip van die onderlinge verband tussen wetenskap en tegnologie, die samelewing en die omgewing te toon.

Dit word bewys as die leerder:

3.1 wetenskap as ‘n menslike aktiwiteit kan verstaan;

3.2 volhoubare gebruik van die aarde se hulpbronne verstaan.

Memorandum

Opdrag 1

ELEKTRISITEITSEENHEDE

Die hoeveelheid elektrisiteit wat toestelle gebruik, hang af van die tipe toestel en hoe lank toestelle gebruik word. Oor die algemeen sal verhittingstoestelle soos oonde, ketels en geysers baie meer verbruik en ook meer kos. Baie skerp halogeen gloeilampe (“spotlights”) verbruik ook baie elektrisiteit.

Toestelle met mikroskyfies in of klein motortjies soos elektriese tandeborsels en skeermesse sal weer minder gebruik.

Elke toestel word gemerk met sy watt-waarde . Ons noem dit die DRYWYING van die toestel. Dit is gewoonlik op die omhulsel, soos by gloeilampe. Die 100 Watt-gloeilamp sal sterker brand as die 60-Watt gloeilamp. Die hoeveelheid Watt beteken eintlik hoeveel elektrisiteit per sekonde deur die toestel gebruik sal word.

Aangesien Watt ‘n relatiewe klein eenheid is, praat ons eerder van kilowatt (kW)

  • 1 kW = 1000 W

‘n Kilowatt-uur (kWh) word weer gelees as die hoeveelheid elektrisiteit wat ‘n 1kW toestel sou gebruik in een uur of ‘n 100 W toestel oor 10 ure. Dit is ook die eenheid waarin elektrisiteit aan die verbruiker verkoop word.

So sou ‘n 100 W gloeilamp vir 10 ure brand. Jou pa se elektriese boor ( 500W) sal net vir 2 ure kon werk met 1kWh.

Ander toestelwaardes:

TOESTEL AANGEDUIDE DRYWING HOOG OF LAAG?
Radio 26/32 W L
Tv 80 W L
Strykyster 1200 W H
Sakrekenaar 0.0006 W Baie L
Rekenaar 280 W H
Boor 500 W H
Stoof 1000 W H
Mikrogolfoond 750 W H
Ketel ? H
Broodrooster ?

Ons weet nou dat elektrisiteit in die eenheid kilowatt per uur verkoop – kW/uur

  • 1 kWh is die hoeveelheid elektriese energie wat ‘n toestel met ‘n drywing van 1 kW in een uur gebruik.

Om kWh te bereken, moet ons net die volgende formule gebruik:

  • KWh = drywing x tyd

Om te bereken hoeveel energie ‘n haardroër (1500W) gebruik het in 20 minute

  • KWh = drywing x tyd
  • 1 500w /1000w x 0.3
  • = 0.45 kWh

Om die koste van die gebruik van ‘n elektriese toestel uit te werk, word die volgende formule gebruik:

  • Koste = elektriese energie in kWh x koste van 1 kWh

As 1 kWh 50c kos, sal ‘n haardroër se gebruik die volgende kos:

  • Koste = 0.45 kWh x 50c
  • = R 2,25

Questions & Answers

how did you get 1640
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If auger is pair are the roots of equation x2+5x-3=0
Peter Reply
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MATTHEW Reply
420
Sharon
from theory: distance [miles] = speed [mph] × time [hours] info #1 speed_Dennis × 1.5 = speed_Wayne × 2 => speed_Wayne = 0.75 × speed_Dennis (i) info #2 speed_Dennis = speed_Wayne + 7 [mph] (ii) use (i) in (ii) => [...] speed_Dennis = 28 mph speed_Wayne = 21 mph
George
Let W be Wayne's speed in miles per hour and D be Dennis's speed in miles per hour. We know that W + 7 = D and W * 2 = D * 1.5. Substituting the first equation into the second: W * 2 = (W + 7) * 1.5 W * 2 = W * 1.5 + 7 * 1.5 0.5 * W = 7 * 1.5 W = 7 * 3 or 21 W is 21 D = W + 7 D = 21 + 7 D = 28
Salma
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SIMRAN Reply
-42m²+60m-18
Salma
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-24m+3+3mÁ^2
Susan
i really want to learn
Amira
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Hw did u arrive to this answer.
Aphelele
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Bajemah
-6m(3mA²+4m-3)+6(3mA²+4m-3) =-18m²A²-24m²+18m+18mA²+24m-18 Rearrange like items -18m²A²-24m²+42m+18A²-18
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please why is it that the 0is in the place of ten thousand
Grace
Send the example to me here and let me see
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however, may I ask you some questions about Algarba?
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mahnoor Reply
I'm guessing, but it's somewhere around $4335.00 I think
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12% of sales will need to exceed 925 - 500, or 425 to exceed fixed amount option. What amount of sales does that equal? 425 ÷ (12÷100) = 3541.67. So the answer is sales greater than 3541.67. Check: Sales = 3542 Commission 12%=425.04 Pay = 500 + 425.04 = 925.04. 925.04 > 925.00
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Source:  OpenStax, Natuurwetenskappe graad 8. OpenStax CNX. Sep 12, 2009 Download for free at http://cnx.org/content/col11049/1.1
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