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Then the new code decodes the strings into JSONObject objects using a parse method from the JSONParser class and saves them in a fourth ArrayList object.

The contents of both lists of JSONObject objects are displayed on the computer screen after they are populated with decoded data fromthe JSON strings.

Decode and display using the JSONValue class

I will explain this program in fragments, and will begin at the point where the new code begins. The first fragment is shown in Listing 1 .

Listing 1 . Decode and display using the JSONValue class. //Create a container for decoded JSON strings. ArrayList<JSONObject>listC = new ArrayList<JSONObject>(); //Decode and display JSON strings using the parse method of the// JSONValue class System.out.println("Decode using JSONValue class");decodeC(listB,listC); display(listC);System.out.println();//blank line

Immediately prior to the code in Listing 1 , three JSON strings are stored as elements in an ArrayList object referred to as listB .

Listing 1 begins by instantiating a new ArrayList object, referred to as listC that will receive the decoded versions of the JSON strings as type JSONObject objects. Then Listing 1 calls the method named decodeC passing the list of JSON strings and the empty list as parameters.

The method named decodeC

The method named decodeC is shown in its entirety in Listing 2 .

Listing 2 . The method named decodeC. static void decodeC(ArrayList input,ArrayList output){ String temp = null;Iterator<String>iterator = input.iterator(); while (iterator.hasNext()){temp = iterator.next(); output.add(JSONValue.parse(temp));}//end while loop }//end decodeC

This method decodes a list of JSON strings into JSONObject objects using a static parse method of the JSONValue class. The resulting JSONObject objects are added to the empty ArrayList object received as an incoming parameter. When the method returns, that list contains one JSONObject object for each JSON string contained in the incoming ArrayList object.

Display contents of JSONObject objects

Returning now to the code in Listing 1 , the next statement calls the display method passing the now-populated listC as a parameter. At this point, the JSONObject objects stored in listC contain the information that was extracted from the JSON strings by the parse method of the JSONValue class.

The display method is shown in its entirety in Listing 3 .

Listing 3 . The display method. static void display(ArrayList input){ JSONObject temp = null;Iterator<JSONObject>iterator = input.iterator(); while (iterator.hasNext()){temp = iterator.next(); System.out.print("Name: " + temp.get("name"));System.out.print(" Age: " + temp.get("age")); System.out.println(" Is student? " + temp.get("student"));}//end while loop }//end display

This method uses the get method inherited from the HashMap class to get and display the values in a list of JSONObject objects for a known set of keys. This is plain-vanilla Java code and shouldn't require further explanation. The results of this call to the display method are shown in the top half of Figure 1 .

Questions & Answers

what is the coefficient of -4×
Mehri Reply
the operation * is x * y =x + y/ 1+(x × y) show if the operation is commutative if x × y is not equal to -1
Alfred Reply
An investment account was opened with an initial deposit of $9,600 and earns 7.4% interest, compounded continuously. How much will the account be worth after 15 years?
Kala Reply
lim x to infinity e^1-e^-1/log(1+x)
given eccentricity and a point find the equiation
Moses Reply
12, 17, 22.... 25th term
Alexandra Reply
12, 17, 22.... 25th term
College algebra is really hard?
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I'm 13 and I understand it great
I am 1 year old but I can do it! 1+1=2 proof very hard for me though.
Not really they are just easy concepts which can be understood if you have great basics. I am 14 I understood them easily.
find the 15th term of the geometric sequince whose first is 18 and last term of 387
Jerwin Reply
I know this work
The given of f(x=x-2. then what is the value of this f(3) 5f(x+1)
virgelyn Reply
hmm well what is the answer
If f(x) = x-2 then, f(3) when 5f(x+1) 5((3-2)+1) 5(1+1) 5(2) 10
how do they get the third part x = (32)5/4
kinnecy Reply
make 5/4 into a mixed number, make that a decimal, and then multiply 32 by the decimal 5/4 turns out to be
can someone help me with some logarithmic and exponential equations.
Jeffrey Reply
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it think it's written 20/(X-6)^2 so it's 20 divided by X-6 squared
I'm not sure why it wrote it the other way
I got X =-6
ok. so take the square root of both sides, now you have plus or minus the square root of 20= x-6
oops. ignore that.
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is it a question of log
I rally confuse this number And equations too I need exactly help
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Commplementary angles
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what is a good calculator for all algebra; would a Casio fx 260 work with all algebra equations? please name the cheapest, thanks.
Kevin Reply
a perfect square v²+2v+_
Dearan Reply
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Abdirahman Reply
A soccer field is a rectangle 130 meters wide and 110 meters long. The coach asks players to run from one corner to the other corner diagonally across. What is that distance, to the nearest tenths place.
Kimberly Reply
Jeannette has $5 and $10 bills in her wallet. The number of fives is three more than six times the number of tens. Let t represent the number of tens. Write an expression for the number of fives.
August Reply
What is the expressiin for seven less than four times the number of nickels
Leonardo Reply
How do i figure this problem out.
how do you translate this in Algebraic Expressions
linda Reply
why surface tension is zero at critical temperature
I think if critical temperature denote high temperature then a liquid stats boils that time the water stats to evaporate so some moles of h2o to up and due to high temp the bonding break they have low density so it can be a reason
Need to simplify the expresin. 3/7 (x+y)-1/7 (x-1)=
Crystal Reply
. After 3 months on a diet, Lisa had lost 12% of her original weight. She lost 21 pounds. What was Lisa's original weight?
Chris Reply
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Source:  OpenStax, Object-oriented programming (oop) with java. OpenStax CNX. Jun 29, 2016 Download for free at https://legacy.cnx.org/content/col11441/1.201
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