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Discounts and proceeds

Banks often deduct the simple interest from the loan amount at the time that the loan is made. When this happens, we say the loan has been discounted . The interest that is deducted is called the discount , and the actual amount that is given to the borrower is called the proceeds . The amount the borrower is obligated to repay is called the maturity value .

Discount and proceeds

If an amount M size 12{M} {} is borrowed for a time t size 12{t} {} at a discount rate of r size 12{r} {} per year, then the discount D size 12{D} {} is

D = M r t size 12{D=M cdot r cdot t} {}

The proceeds P size 12{P} {} , the actual amount the borrower gets, is given by

P = M D size 12{P=M - D} {}

P = M Mrt size 12{P=M - ital "Mrt"} {}

or P = M 1 rt size 12{P=M left (1 - ital "rt" right )} {}

Where interest rate r size 12{r} {} is expressed in decimals.

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Francisco borrows $1200 for 10 months at a simple interest rate of 15% per year. Determine the discount and the proceeds.

The discount D size 12{D} {} is the interest on the loan that the bank deducts from the loan amount.

D = Mrt size 12{D= ital "Mrt"} {}
D = $ 1200 .15 10 12 = $ 150 size 12{ matrix { D=$"1200" left ( "." "15" right ) left ( { {"10"} over {"12"} } right ) {} ##=$"150" } } {}

Therefore, the bank deducts $150 from the maturity value of $1200, and gives Francisco $1050. Francisco is obligated to repay the bank $1200.

In this case, the discount D = $ 150 size 12{D=$"150"} {} , and the proceeds P = $ 1200 $ 150 = $ 1050 size 12{P=$"1200" - $"150"=$"1050"} {} .

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If Francisco wants to receive $1200 for 10 months at a simple interest rate of 15% per year, what amount of loan should he apply for?

In this problem, we are given the proceeds P and are being asked to find the maturity value M size 12{M} {} .

We have P = $ 1200 size 12{P=$"1200"} {} , r = . 15 size 12{r= "." "15"} {} , t = 10 / 12 size 12{t="10"/"12"} {} . We need to find M size 12{M} {} .

We know

P = M D size 12{P=M - D} {}

but

D = Mrt size 12{D= ital "Mrt"} {}

therefore

P = M Mrt size 12{P=M - ital "Mrt"} {}
P = M 1 rt size 12{P=M left (1 - ital "rt" right )} {}
$ 1200 = M 1 . 15 10 12 $ 1200 = M 1 . 125 $ 1200 = M . 875 $ 1200 . 875 = M $ 1371 . 43 = M size 12{ matrix { $"1200"=M left [1 - left ( "." "15" right ) left ( { {"10"} over {"12"} } right ) right ]{} ## $"1200"=M left (1 - "." "125" right ) {} ##$"1200"=M left ( "." "875" right ) {} ## { {$"1200"} over { "." "875"} } =M {} ##$"1371" "." "43"=M } } {}

Therefore, Francisco should ask for a loan for $1371.43.

The bank will discount $171.43 and Francisco will receive $1200.

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Compound interest

Section overview

In this section you will learn to:

  1. Find the future value of a lump-sum.
  2. Find the present value of a lump-sum.
  3. Find the effective interest rate.

In the [link] , we did problems involving simple interest. Simple interest is charged when the lending period is short and often less than a year. When the money is loaned or borrowed for a longer time period, the interest is paid (or charged) not only on the principal, but also on the past interest, and we say the interest is compounded .

Suppose we deposit $200 in an account that pays 8% interest. At the end of one year, we will have $ 200 + $ 200 . 08 = $ 200 1 + . 08 = $ 216 size 12{$"200"+$"200" left ( "." "08" right )=$"200" left (1+ "." "08" right )=$"216"} {} .

Now suppose we put this amount, $216, in the same account. After another year, we will have $ 216 + $ 216 . 08 = $ 216 1 + . 08 = $ 233 . 28 size 12{$"216"+$"216" left ( "." "08" right )=$"216" left (1+ "." "08" right )=$"233" "." "28"} {} .

So an initial deposit of $200 has accumulated to $233.28 in two years. Further note that had it been simple interest, this amount would have accumulated to only $232. The reason the amount is slightly higher is because the interest ($16) we earned the first year, was put back into the account. And this $16 amount itself earned for one year an interest of $ 16 . 08 = $ 1 . 28 size 12{$"16" left ( "." "08" right )=$1 "." "28"} {} , thus resulting in the increase. So we have earned interest on the principal as well as on the past interest, and that is why we call it compound interest.

Now suppose we leave this amount, $233.28, in the bank for another year, the final amount will be $ 233 . 28 + $ 233 . 28 . 08 = $ 233 . 28 1 + . 08 = $ 251 . 94 size 12{$"233" "." "28"+$"233" "." "28" left ( "." "08" right )=$"233" "." "28" left (1+ "." "08" right )=$"251" "." "94"} {} .

Now let us look at the mathematical part of this problem so that we can devise an easier way to solve these problems.

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Source:  OpenStax, Applied finite mathematics. OpenStax CNX. Jul 16, 2011 Download for free at http://cnx.org/content/col10613/1.5
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