# 1.2 Algebra

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3.2.5 the value of the expression if a = -2

4. Write an algebraic expression for each of the following.

4.1 the product of a and p , multiplied by the sum of a and p .

4.2 the sum of a and p , multiplied by 3

4.3 the quotient of a and p multiplied by 3

4.4 the cost of a bus trip is p rand per km. Calculate the cost of the entire, trip if the distance travelled is 45 km.

4.5 5 is added to the product of 3 and a , and the answer is reduced by the sum of 9 and b

5. You rent a car at Cape Town International airport at R 125,50 per day.

5.1 Compile a table to indicate how much it will cost you in hire for the following periods: 6; 7; ..... 12 days.

5.2 Determine a formula for representing the data with y (total cost) and $x$ (number of days).

5.3 What will the total hiring costs for 2½ months come to?

6. How many terms in each of the following expressions?

6.1 a b + m / n - 2( a + b )

6.2 ( p + q + r )3 - 4 r ²

6.3 m / n + 7 m ² ÷ 5 x p - q x r

6.4 (6 x q ) ÷ ( r x 7)

6.5 $\frac{\text{mn - pr - a}}{5}$

Assessment

 Assessment of myself: by myself: Assessment by Teacher: I can…    1 2 3 4 Critical Outcomes 1 2 3 4 distinguish between the terms of a polynomial; (Lo 2.4; 2.8.2; 2.9) Critical and creative thinking identify the coefficient of an unknown; (Lo 2.4; 2.9) Collaborating identify the constant in a polynomial; (Lo 2.4; 2.9) Organising en managing determine the degree of an expression; (Lo 2.4; 2.9; 2.8.1) Processing of information arrange the expression in a descending order; (Lo 2.4; 2.9) Communication accurately multiply and divide the signs (+ / -); (Lo 2.4; 2.8.4) Problem solving write algebraic expressions; (Lo 2.4; 2.2; 2.8.4) Independence determine the formulas for flow diagrams and tables. (Lo 2.1; 2.3; 2.4; 2.7)

good average not so good

 Comments by the learner: My plan of action: My marks: I am very satisfied with the standard of my work. < Date : I am satisfied with the steady progress I have made. Out of: I have worked hard, but my achievement is not satisfactory. Learner : I did not give my best. >
 Comments by parents: Comments by teacher: Parent signature: Date : Signature: Date :

## Assessment

 Learning outcomes(LOs) LO 2 Patterns Functions and AlgebraThe learner will be able to recognise, describe and represent patterns and relationships, as well as to solve problems, using algebraic language and skills. We know this when the learner : 2.1 investigates and extends numerical and geometrical patterns to find relationships and rules, including patterns that:2.1.1 are presented in physical or diagrammatic form;2.1.2 are not limited to series with constant difference or ratio;2.1.3 occur in natural and cultural contexts; 2.1.4 are created by the learner him/herself;2.1.5 are presented in tables;2.1.6 are presented algebraically; 2.2 describes, explains and justifies observed relationships or rules in own words or in algebra; 2.3 represents and uses relationships between variables to determine input an output values in a variety of ways by making use of:2.3.1 verbal descriptions;2.3.2 flow diagrams;2.3.3 tables;2.3.4 formulas and equations; 2.4 builds mathematical models that represent, describe and provide solutions to problem situations, thereby revealing responsibility towards the environment and the health of other people (including problems in the contexts of human rights, social, economic, cultural and environmental issues); 2.7 is able to determine, analyse and interpret the equivalence of different descriptions of the same relationship or rule which can be represented:2.7.1 verbally;2.7.2 by means of flow diagrams;2.7.3 in tables;2.7.4 by means of equations or expressions to thereby select the most practical representation of a given situation; 2.8 is able to use conventions of algebraic notation and the variable, reconcilable and distributive laws to:2.8.1 classify terms like even and odd and to account for the classification;2.8.2 assemble equal terms;2.8.3 multiply or divide an algebraic expression with one, two, or three terms by a monomial; 2.8.4 simplify algebraic expressions in bracketed notation using one or two sets of brackets and two types of operation;2.8.5 compare different versions of algebraic expressions having one or two operations, select those that are equivalent and motivate the selected examples;2.8.6 rewrite algebraic expressions, formulas or equations in context in simpler or more usable form; 2.9 is able to interpret and use the following algebraic ideas in context: term, expression, coefficient, exponent (or index), basis, constant, variable, equation, formula (or rule).

## Class assignment 1

• 2
• $-\frac{1}{4}$
• 6
• 2

2.1 x + 7

2.2 x + 7

2.3 a – b

• ( x + 7) – 6

= x – 13

• x x $b$ = x $b$
• $\frac{x}{7}$
• $a$ 2
• $\sqrt{a}$

2.9 $\text{ab}$ – ( $a$ $b$ )

3.1 a c

7 -4

3.2 a c

9 $-\frac{1}{2}$

4. 21; 31; 95; $y=2x+1$

## Homework assignment 1

• y = 2 x + 6
• y = 5 x – 3
• y = x 2
• y = x 3
• y = x 2 + 1
• Sketch: (3 x 4) + 1 = 13
• y = 3 x + 1
• y = 3(110) + 1 = 331
• (2 005 – 1) ÷ 3 = 668
• 7 – $\frac{1}{4}a$ + $\frac{{a}^{2}}{5}$ + 3 ${a}^{3}$
• 4
• $\frac{1}{5}$
• 3
• 7
• $-\frac{1}{4}\left(-\frac{2}{1}\right)$ + ${\left(\frac{-2}{5}\right)}^{2}$ + 7 3(-2) 3

= $\frac{1}{2}$ + $\frac{4}{5}$ + 7 – 24

= $\frac{5+8+\text{70}-\text{240}}{\text{10}}$

= $\frac{-\text{157}}{\text{10}}$ = -15,7

• ap + ( a + p )
• 3( a + p )
• $\frac{a}{p}$ + 3
• 45 p
• (3 a + 5) – (9 + b )

5.1

 Days 6 7 8 9 10 11 12 R 753 878,50 1 004 1 629,50 1 255 1 380,50 1 506
• y = 125,5 x
• 2 $\frac{1}{2}$ months (2 x 30 ) + 15 75 x R125,50 = R9 412,50

or (30 + 31 + 15) 76 x R125,50 = R9 538,00

• 3
• 2
• 3
• 1
• 1

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research.net
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sciencedirect big data base
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absolutely yes
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in general
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On having this app for quite a bit time, Haven't realised there's a chat room in it.
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