<< Chapter < Page Chapter >> Page >

Functions of the form y = a b ( x ) + q

Functions of the form y = a b ( x ) + q are known as exponential functions. The general shape of a graph of a function of this form is shown in [link] .

General shape and position of the graph of a function of the form f ( x ) = a b ( x ) + q .

Investigation : functions of the form y = a b ( x ) + q

  1. On the same set of axes, plot the following graphs:
    1. a ( x ) = - 2 · b ( x ) + 1
    2. b ( x ) = - 1 · b ( x ) + 1
    3. c ( x ) = 0 · b ( x ) + 1
    4. d ( x ) = 1 · b ( x ) + 1
    5. e ( x ) = 2 · b ( x ) + 1
    Use your results to deduce the effect of a .
  2. On the same set of axes, plot the following graphs:
    1. f ( x ) = 1 · b ( x ) - 2
    2. g ( x ) = 1 · b ( x ) - 1
    3. h ( x ) = 1 · b ( x ) + 0
    4. j ( x ) = 1 · b ( x ) + 1
    5. k ( x ) = 1 · b ( x ) + 2
    Use your results to deduce the effect of q .

You should have found that the value of a affects whether the graph curves upwards ( a > 0 ) or curves downwards ( a < 0 ).

You should have also found that the value of q affects the position of the y -intercept.

These different properties are summarised in [link] .

Table summarising general shapes and positions of functions of the form y = a b ( x ) + q .
a > 0 a < 0
q > 0
q < 0

Domain and range

For y = a b ( x ) + q , the function is defined for all real values of x . Therefore, the domain is { x : x R } .

The range of y = a b ( x ) + q is dependent on the sign of a .

If a > 0 then:

b ( x ) 0 a · b ( x ) 0 a · b ( x ) + q q f ( x ) q

Therefore, if a > 0 , then the range is { f ( x ) : f ( x ) [ q ; ) } .

If a < 0 then:

b ( x ) 0 a · b ( x ) 0 a · b ( x ) + q q f ( x ) q

Therefore, if a < 0 , then the range is { f ( x ) : f ( x ) ( - ; q ] } .

For example, the domain of g ( x ) = 3 · 2 x + 2 is { x : x R } . For the range,

2 x 0 3 · 2 x 0 3 · 2 x + 2 2

Therefore the range is { g ( x ) : g ( x ) [ 2 ; ) } .

Intercepts

For functions of the form, y = a b ( x ) + q , the intercepts with the x and y axis is calculated by setting x = 0 for the y -intercept and by setting y = 0 for the x -intercept.

The y -intercept is calculated as follows:

y = a b ( x ) + q y i n t = a b ( 0 ) + q = a ( 1 ) + q = a + q

For example, the y -intercept of g ( x ) = 3 · 2 x + 2 is given by setting x = 0 to get:

y = 3 · 2 x + 2 y i n t = 3 · 2 0 + 2 = 3 + 2 = 5

The x -intercepts are calculated by setting y = 0 as follows:

y = a b ( x ) + q 0 = a b ( x i n t ) + q a b ( x i n t ) = - q b ( x i n t ) = - q a

Which only has a real solution if either a < 0 or q < 0 . Otherwise, the graph of the function of form y = a b ( x ) + q does not have any x -intercepts.

For example, the x -intercept of g ( x ) = 3 · 2 x + 2 is given by setting y = 0 to get:

y = 3 · 2 x + 2 0 = 3 · 2 x i n t + 2 - 2 = 3 · 2 x i n t 2 x i n t = - 2 3

which has no real solution. Therefore, the graph of g ( x ) = 3 · 2 x + 2 does not have any x -intercepts.

Asymptotes

Functions of the form y = a b ( x ) + q have a single horizontal asymptote. The asymptote can be determined by examining the range.

We have seen that the range is controlled by the value of q. If a > 0 , then the range is { f ( x ) : f ( x ) [ q ; ) } .And if a > 0 , then the range is { f ( x ) : f ( x ) [ q ; ) } .

This shows that the function tends towards the value of q as x . Therefore the horizontal asymptote lies at x = q .

Sketching graphs of the form f ( x ) = a b ( x ) + q

In order to sketch graphs of functions of the form, f ( x ) = a b ( x ) + q , we need to determine four characteristics:

  1. domain and range
  2. asymptote
  3. y -intercept
  4. x -intercept

For example, sketch the graph of g ( x ) = 3 · 2 x + 2 . Mark the intercepts.

We have determined the domain to be { x : x R } and the range to be { g ( x ) : g ( x ) [ 2 , ) } .

The y -intercept is y i n t = 5 and there are no x -intercepts.

Graph of g ( x ) = 3 · 2 x + 2 .

Draw the graph of y = - 2 . 3 x + 5 .

  1. The domain is: { x : x R } and the range is: { f ( x ) : f ( x ) ( - ; 5 ] } .
  2. There is one asymptote for functions of this form. This occurs at y = q . So the asymptote for this graph is at y = 5
  3. The y-intercept occurs when x = 0 .
    y = - 2 . 3 x + 5 y = - 2 . 3 0 + 5 y = - 2 ( 1 ) + 5 y int = 7
    So there is one y-intercept at ( 0 , 7 ) .
  4. The x-intercept occurs when y = 0 . Calculating the x-intercept gives:
    y = - 2 . 3 x + 5 0 = - 2 . 3 x + 5 - 5 = - 2 . 3 x 3 x int = 5 2 x int = 0,83
    So there is one x-intercept at ( 0,83 , 0 ) .
  5. Putting all this together gives us the following graph:

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, Maths grade 10 rought draft. OpenStax CNX. Sep 29, 2011 Download for free at http://cnx.org/content/col11363/1.1
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'Maths grade 10 rought draft' conversation and receive update notifications?

Ask