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For example,

2 - 7 = 1 2 × 2 × 2 × 2 × 2 × 2 × 2 = 1 2 7

Application using exponential law 3: a - n = 1 a n , a 0

  1. 2 - 2 = 1 2 2
  2. 2 - 2 3 2
  3. ( 2 3 ) - 3
  4. m n - 4
  5. a - 3 · x 4 a 5 · x - 2

Exponential law 4: a m ÷ a n = a m - n

We already realised with law 3 that a minus sign is another way of saying that the exponential number is to be divided instead of multiplied. Law 4 is just a more general way of saying the same thing. We get this law by multiplying law 3 by a m on both sides and using law 2.

a m a n = a m a - n = a m - n

For example,

2 7 ÷ 2 3 = 2 × 2 × 2 × 2 × 2 × 2 × 2 2 × 2 × 2 = 2 × 2 × 2 × 2 = 2 4 = 2 7 - 3

Khan academy video on exponents - 4

Application using exponential law 4: a m ÷ a n = a m - n

  1. a 6 a 2 = a 6 - 2
  2. 3 2 3 6
  3. 32 a 2 4 a 8
  4. a 3 x a 4

Exponential law 5: ( a b ) n = a n b n

The order in which two real numbers are multiplied together does not matter. Therefore,

( a b ) n = a × b × a × b × ... × a × b ( n times ) = a × a × ... × a ( n times ) × b × b × ... × b ( n times ) = a n b n

For example,

( 2 · 3 ) 4 = ( 2 · 3 ) × ( 2 · 3 ) × ( 2 · 3 ) × ( 2 · 3 ) = ( 2 × 2 × 2 × 2 ) × ( 3 × 3 × 3 × 3 ) = ( 2 4 ) × ( 3 4 ) = 2 4 3 4

Application using exponential law 5: ( a b ) n = a n b n

  1. ( 2 x y ) 3 = 2 3 x 3 y 3
  2. ( 7 a b ) 2
  3. ( 5 a ) 3

Exponential law 6: ( a m ) n = a m n

We can find the exponential of an exponential of a number. An exponential of a number is just a real number. So, even though the sentence sounds complicated, it is just saying that you can find the exponential of a number and then take the exponential of that number. You just take the exponential twice, using the answer of the first exponential as the argument for the second one.

( a m ) n = a m × a m × ... × a m ( n times ) = a × a × ... × a ( m × n times ) = a m n

For example,

( 2 2 ) 3 = ( 2 2 ) × ( 2 2 ) × ( 2 2 ) = ( 2 × 2 ) × ( 2 × 2 ) × ( 2 × 2 ) = ( 2 6 ) = 2 ( 2 × 3 )

Application using exponential law 6: ( a m ) n = a m n

  1. ( x 3 ) 4
  2. [ ( a 4 ) 3 ] 2
  3. ( 3 n + 3 ) 2

Simplify: 5 2 x - 1 · 9 x - 2 15 2 x - 3

  1. = 5 2 x - 1 · ( 3 2 ) x - 2 ( 5 . 3 ) 2 x - 3 = 5 2 x - 1 · 3 2 x - 4 5 2 x - 3 · 3 2 x - 3
  2. = 5 2 x - 1 - 2 x + 3 · 3 2 x - 4 - 2 x + 3 = 5 2 · 3 - 1
  3. = 25 3

Investigation : exponential numbers

Match the answers to the questions, by filling in the correct answer into the Answer column. Possible answers are: 3 2 , 1, - 1 , - 1 3 , 8. Answers may be repeated.

Question Answer
2 3
7 3 - 3
( 2 3 ) - 1
8 7 - 6
( - 3 ) - 1
( - 1 ) 23

The following video gives an example on using some of the concepts covered in this chapter.

Khan academy video on exponents - 5

Summary

  • Exponential notation means a number written like a n where n is an integer and a can be any real number.
  • a is called the base and n is called the exponent or index .
  • The n th power of a is defined as: a n = a × a × × a ( n times )
  • There are six laws of exponents:
    • Exponential Law 1: a 0 = 1
    • Exponential Law 2: a m × a n = a m + n
    • Exponential Law 3: a - n = 1 a n , a 0
    • Exponential Law 4: a m ÷ a n = a m - n
    • Exponential Law 5: ( a b ) n = a n b n
    • Exponential Law 6: ( a m ) n = a m n

End of chapter exercises

  1. Simplify as far as possible:
    1. 302 0
    2. 1 0
    3. ( x y z ) 0
    4. [ ( 3 x 4 y 7 z 12 ) 5 ( - 5 x 9 y 3 z 4 ) 2 ] 0
    5. ( 2 x ) 3
    6. ( - 2 x ) 3
    7. ( 2 x ) 4
    8. ( - 2 x ) 4

  2. Simplify without using a calculator. Leave your answers with positive exponents.
    1. 3 x - 3 ( 3 x ) 2
    2. 5 x 0 + 8 - 2 - ( 1 2 ) - 2 · 1 x
    3. 5 b - 3 5 b + 1

  3. Simplify, showing all steps:
    1. 2 a - 2 . 3 a + 3 6 a
    2. a 2 m + n + p a m + n + p · a m
    3. 3 n · 9 n - 3 27 n - 1
    4. ( 2 x 2 a y - b ) 3
    5. 2 3 x - 1 · 8 x + 1 4 2 x - 2
    6. 6 2 x · 11 2 x 22 2 x - 1 · 3 2 x

  4. Simplify, without using a calculator:
    1. ( - 3 ) - 3 · ( - 3 ) 2 ( - 3 ) - 4
    2. ( 3 - 1 + 2 - 1 ) - 1
    3. 9 n - 1 · 27 3 - 2 n 81 2 - n
    4. 2 3 n + 2 · 8 n - 3 4 3 n - 2

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Source:  OpenStax, Siyavula textbooks: grade 10 maths [ncs]. OpenStax CNX. Aug 05, 2011 Download for free at http://cnx.org/content/col11239/1.2
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