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Answer 5

True. The JSONArray class provides two overloaded versions of the method named toJSONString . One is an instance method and the other is a static method. On a side note, this is also true of the class named JSONObject .

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Answer 4

False. The code in Listing 2 produces the screen output shown in Figure 4 . Unlike an object of the JSONObject class, an object of the JSONArray class is an ordered list. By this we meanthat the user has precise control over where in the list each element is inserted. The user can access elements by their integer index (position in the list) .

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Answer 3

False. The code in Listing 1 produces the screen output with the errors shown in Figure 2 . The JSONArray class neither defines nor inherits a method named put .

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Answer 2

False. The JSONArray class extends the ArrayList class, which implements the List interface. Therefore, an object of the JSONArray class is a list and is not an array. For example, the elements in a JSONArray object cannot be accessed using the square bracket ([]) notation commonly associated with Java arrays. Instead, the elements are accessed using the add and get methods declared in the List interface and inherited from the ArrayList class.

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Answer 1

False. The JSONArray class extends the standard Java ArrayList class.

Go back to Question 1

Figures

This section contains Figures that may be referred to by one or more questions or answers.

Figure 1

[{"Name":"Tom"},{"Age":21},{"Student":true}]

Figure 2

Code01.java:22: error: cannot find symbol array.put(jsonObj01);^ symbol: method put(JSONObject)location: variable array of type JSONArray Code01.java:23: error: cannot find symbolarray.put(jsonObj02); ^symbol: method put(JSONObject) location: variable array of type JSONArrayCode01.java:24: error: cannot find symbol array.put(jsonObj03);^ symbol: method put(JSONObject)location: variable array of type JSONArray Note: Code01.java uses unchecked or unsafe operations.Note: Recompile with -Xlint:unchecked for details. 3 errorsError: Could not find or load main class Code01 Press any key to continue . . .

Figure 3

[{"Name":"Tom"},{"Age":21},{"Student":true}]

Figure 4

[{"Name":"Tom"},{"Student":true},{"Age":21}]

Figure 5

[{"Name":"Tom"},{"Age":21},{"Student":true}] [{"Name":"Tom"},{"Age":21},{"Student":true}]

Figure 6

{"person":[{"Student":true},{"Age":21},{"Name":"Tom"}]}

Figure 7

[{"Student":true},{"Age":21},{"Name":"Tom"}]

Figure 8

{"person":[{"Name":"Tom"},{"Age":21},{"Name":"Tom"}]}

Listings

This section contains Listings that may be referred to by one or more questions or answers.

Listing 1

/************************************************ Copyright: R.G.Baldwin 2016Tested with Java 8, Windows 7, and json-simple-1.1.1.************************************************/ import org.json.simple.JSONObject;import org.json.simple.JSONArray; class Code01{public static void main(String[] args){JSONObject jsonObj01 = new JSONObject(); jsonObj01.put("Name","Tom");JSONObject jsonObj02 = new JSONObject(); jsonObj02.put("Age",21);JSONObject jsonObj03 = new JSONObject(); jsonObj03.put("Student",true);JSONArray array = new JSONArray();array.put(jsonObj01); array.put(jsonObj02);array.put(jsonObj03); System.out.println(array.toJSONString());}//end main}//end class Code01

Questions & Answers

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Step 1: Find the mean. To find the mean, add up all the scores, then divide them by the number of scores. ... Step 2: Find each score's deviation from the mean. ... Step 3: Square each deviation from the mean. ... Step 4: Find the sum of squares. ... Step 5: Divide the sum of squares by n – 1 or N.
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The sample of 16 students is taken. The average age in the sample was 22 years with astandard deviation of 6 years. Construct a 95% confidence interval for the age of the population.
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Bhartdarshan' is an internet-based travel agency wherein customer can see videos of the cities they plant to visit. The number of hits daily is a normally distributed random variable with a mean of 10,000 and a standard deviation of 2,400 a. what is the probability of getting more than 12,000 hits? b. what is the probability of getting fewer than 9,000 hits?
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Bhartdarshan'is an internet-based travel agency wherein customer can see videos of the cities they plan to visit. The number of hits daily is a normally distributed random variable with a mean of 10,000 and a standard deviation of 2,400. a. What is the probability of getting more than 12,000 hits
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Source:  OpenStax, Object-oriented programming (oop) with java. OpenStax CNX. Jun 29, 2016 Download for free at https://legacy.cnx.org/content/col11441/1.201
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