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Listing 5 shows how to modify an item in a list using a subscription.
Listing 5 . Answer 18. |
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listA = [3.14,59,"A string",1024]
listA[2]= "New string" |
Go back to Question 18
Listing 4 shows how to concatenate two lists.
Listing 4 . Answer 17. |
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listA = [3.14,59,"A string",1024]
listB = [2,4,6,16]listC = listA + listB |
Go back to Question 17
Listing 3 shows how to access a slice from a list.
Listing 3 . Answer 16. |
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print(theList[0:3]) |
Go back to Question 16
Listing 2 shows how to access an item in a list using a subscription.
Listing 2 . Answer 15. |
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print(theList[2]) |
Go back to Question 15
Listing 1 shows a simple list.
Listing 1 . Answer 14. |
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theList = [3.14,59,"A string",1024] |
Go back to Question 14
Lists are formed by placing a comma-separated sequence of expressions in square brackets.
Go back to Question 13
The items of a list are arbitrary Python objects.
Go back to Question 12
False. The characters in a string cannot be modified after the string is created.
Go back to Question 11
True. A string is a sequence.
Go back to Question 10
Mutable sequences can be changed after they are created.
Go back to Question 9
A dictionary.
Go back to Question 8
False. There is no character type in Python. Rather, a string's items are characters. A character is not a separate data type but a string containingexactly one character.
Go back to Question 7
The last item in the sequence is selected for an index value of -1.
Go back to Question 6
False. The integers may be positive or negative.
Go back to Question 5
If the primary is a sequence , the expression_list must evaluate to an integer or a slice.
Go back to Question 4
The primary must evaluate to an object of a sequence or mapping type.
Go back to Question 3
string, tuple and list and possibly range object
Go back to Question 2
False in the Python context. In Python, A subscription selects an item of a sequence object.
Go back to Question 1
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Affiliation : I am a professor of Computer Information Technology at Austin Community College in Austin, TX.
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