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An abstract method doesn't have a body.

Abstract classes and methods

A class that contains an abstract method must itself be declared abstract . However, an abstract class is not required to contain abstract methods.

Failed to declare the class abstract

In this program, the class named Base contains an abstract method named test , but the class is not declared abstract as required.

class Base{ abstract public void test();}//end class Base

Therefore, the program produces the following compiler error under JDK 1.3:

Ap122.java:24: Base should be declared abstract;it does not define test in Base class Base{

Back to Question 3

Answer 2

C. A

Explanation 2

If you missed this ...

If you missed this question, you didn't pay attention to the explanation for Question 1 .

Define a method in a subclass

This program defines a subclass named A that extends a superclass named Base . A method named test is defined in the subclass named A but is not defined in any superclass of the class named A .

Store a reference as a superclass type

The program declares a reference variable of the superclass type, and stores a reference to an object of the subclass in that reference variable as shown inthe following code fragment.

Base myVar = new A();

Downcast and call the method

Then the program calls the method named test on the reference stored as the superclass type, as shown in the following fragment.

((A)myVar).test();

Unlike the program in Question 1 , the reference is downcast to the true type of the object before calling the method named test . As a result, this program does not produce a compiler error.

Why is the cast required?

As explained in Question 1 , it is allowable to store a reference to a subclass object in a variable of a superclass type. Also,as explained in Question 1 , it is not allowable to directly call, on that superclass reference, a method of the subclass objectthat is not defined in or inherited into the superclass.

However, such a call is allowable if the programmer purposely downcasts the reference to the true type of the object before calling the method.

Back to Question 2

Answer 1

A. Compiler Error

Explanation 1

Define a method in a subclass

This program defines a subclass named A that extends a superclass named Base . A method named test , is defined in the subclass named A , which is not defined in any superclass of the class named A .

Store a reference as superclass type

The program declares a reference variable of the superclass type, and stores a reference to an object of the subclass in that reference variable as shown inthe following code fragment.

Base myVar = new A();

Note that no cast is required to store a reference to a subclass object in a reference variable of a superclass type. The required type conversion happensautomatically in this case.

Call a method on the reference

Then the program attempts to call the method named test on the reference stored as the superclass type, as shown in the following fragment.This produces a compiler error.

myVar.test();

The reason for the error

It is allowable to store a reference to a subclass object in a variable of a superclass type. However, it is not allowable to directly call, (on that superclass reference) , a method of the subclass object that is not defined in or inherited into the superclass.

The following error message is produced by JDK 1.3.

Ap120.java:18: cannot resolve symbol symbol : method test ()location: class Base myVar.test();

The solution is ...

This error can be avoided by casting the reference to type A before calling the method as shown below:

((A)myVar).test();

Back to Question 1

-end-

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Source:  OpenStax, Object-oriented programming (oop) with java. OpenStax CNX. Jun 29, 2016 Download for free at https://legacy.cnx.org/content/col11441/1.201
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