<< Chapter < Page Chapter >> Page >

If the graphs of two linear functions are perpendicular, describe the relationship between the slopes and the y -intercepts.

Got questions? Get instant answers now!

If a horizontal line has the equation f ( x ) = a and a vertical line has the equation x = a , what is the point of intersection? Explain why what you found is the point of intersection.

The point of intersection is ( a ,   a ) . This is because for the horizontal line, all of the y coordinates are a and for the vertical line, all of the x coordinates are a . The point of intersection is on both lines and therefore will have these two characteristics.

Got questions? Get instant answers now!

Algebraic

For the following exercises, determine whether the equation of the curve can be written as a linear function.

For the following exercises, determine whether each function is increasing or decreasing.

g ( x ) = 5 x + 6

Increasing

Got questions? Get instant answers now!

b ( x ) = 8 3 x

Decreasing

Got questions? Get instant answers now!

k ( x ) = −4 x + 1

Decreasing

Got questions? Get instant answers now!

p ( x ) = 1 4 x 5

Increasing

Got questions? Get instant answers now!

n ( x ) = 1 3 x 2

Got questions? Get instant answers now!

m ( x ) = 3 8 x + 3

Decreasing

Got questions? Get instant answers now!

For the following exercises, find the slope of the line that passes through the two given points.

( 2 , 4 ) and ( 4 , 10 )

Got questions? Get instant answers now!

( 1 , 5 ) and ( 4 , 11 )

2

Got questions? Get instant answers now!

( –1 , 4 ) and ( 5 , 2 )

Got questions? Get instant answers now!

( 8 , –2 ) and ( 4 , 6 )

–2

Got questions? Get instant answers now!

( 6 , 11 ) and ( –4 , 3 )

Got questions? Get instant answers now!

For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.

f ( 5 ) = −4 , and f ( 5 ) = 2

y = 3 5 x 1

Got questions? Get instant answers now!

f ( −1 ) = 4 , and f ( 5 ) = 1

Got questions? Get instant answers now!

Passes through ( 2 , 4 ) and ( 4 , 10 )

y = 3 x 2

Got questions? Get instant answers now!

Passes through ( 1 , 5 ) and ( 4 , 11 )

Got questions? Get instant answers now!

Passes through ( −1 , 4 ) and ( 5 , 2 )

y = 1 3 x + 11 3

Got questions? Get instant answers now!

Passes through ( −2 , 8 ) and ( 4 , 6 )

Got questions? Get instant answers now!

x intercept at ( −2 , 0 ) and y intercept at ( 0 , −3 )

y = 1.5 x 3

Got questions? Get instant answers now!

x intercept at ( −5 , 0 ) and y intercept at ( 0 , 4 )

Got questions? Get instant answers now!

For the following exercises, determine whether the lines given by the equations below are parallel, perpendicular, or neither.

4 x 7 y = 10 7 x + 4 y = 1

perpendicular

Got questions? Get instant answers now!

3 y + x = 12 y = 8 x + 1

Got questions? Get instant answers now!

3 y + 4 x = 12 6 y = 8 x + 1

parallel

Got questions? Get instant answers now!

6 x 9 y = 10 3 x + 2 y = 1

Got questions? Get instant answers now!

For the following exercises, find the x - and y- intercepts of each equation.

f ( x ) = x + 2

f ( 0 ) = ( 0 ) + 2 f ( 0 ) = 2 y int : ( 0 , 2 ) 0 = x + 2 x int : ( 2 , 0 )

Got questions? Get instant answers now!

h ( x ) = 3 x 5

h ( 0 ) = 3 ( 0 ) 5 h ( 0 ) = 5 y int : ( 0 , 5 ) 0 = 3 x 5 x int : ( 5 3 , 0 )

Got questions? Get instant answers now!

2 x + 5 y = 20

2 x + 5 y = 20 2 ( 0 ) + 5 y = 20 5 y = 20 y = 4 y int : ( 0 , 4 ) 2 x + 5 ( 0 ) = 20 x = 10 x int : ( 10 , 0 )

Got questions? Get instant answers now!

For the following exercises, use the descriptions of each pair of lines given below to find the slopes of Line 1 and Line 2. Is each pair of lines parallel, perpendicular, or neither?

Line 1: Passes through ( 0 , 6 ) and ( 3 , −24 )

Line 2: Passes through ( −1 , 19 ) and ( 8 , −71 )

Line 1: m = –10 Line 2: m = –10 Parallel

Got questions? Get instant answers now!

Line 1: Passes through ( −8 , −55 ) and ( 10 , 89 )

Line 2: Passes through ( 9 , 44 ) and ( 4 , 14 )

Got questions? Get instant answers now!

Line 1: Passes through ( 2 , 3 ) and ( 4 , −1 )

Line 2: Passes through ( 6 , 3 ) and ( 8 , 5 )

Line 1: m = –2 Line 2: m = 1 Neither

Got questions? Get instant answers now!

Line 1: Passes through ( 1 , 7 ) and ( 5 , 5 )

Line 2: Passes through ( −1 , −3 ) and ( 1 , 1 )

Got questions? Get instant answers now!

Line 1: Passes through ( 2 , 5 ) and ( 5 , 1 )

Line 2: Passes through ( −3 , 7 ) and ( 3 , −5 )

Line 1 :   m = 2       Line 2 :   m = 2       Parallel

Got questions? Get instant answers now!

For the following exercises, write an equation for the line described.

Write an equation for a line parallel to f ( x ) = 5 x 3 and passing through the point ( 2 , 12 ) .

Got questions? Get instant answers now!

Write an equation for a line parallel to g ( x ) = 3 x 1 and passing through the point ( 4 , 9 ) .

y = 3 x 3

Got questions? Get instant answers now!

Questions & Answers

if three forces F1.f2 .f3 act at a point on a Cartesian plane in the daigram .....so if the question says write down the x and y components ..... I really don't understand
Syamthanda Reply
hey , can you please explain oxidation reaction & redox ?
Boitumelo Reply
hey , can you please explain oxidation reaction and redox ?
Boitumelo
for grade 12 or grade 11?
Sibulele
the value of V1 and V2
Tumelo Reply
advantages of electrons in a circuit
Rethabile Reply
we're do you find electromagnetism past papers
Ntombifuthi
what a normal force
Tholulwazi Reply
it is the force or component of the force that the surface exert on an object incontact with it and which acts perpendicular to the surface
Sihle
what is physics?
Petrus Reply
what is the half reaction of Potassium and chlorine
Anna Reply
how to calculate coefficient of static friction
Lisa Reply
how to calculate static friction
Lisa
How to calculate a current
Tumelo
how to calculate the magnitude of horizontal component of the applied force
Mogano
How to calculate force
Monambi
a structure of a thermocouple used to measure inner temperature
Anna Reply
a fixed gas of a mass is held at standard pressure temperature of 15 degrees Celsius .Calculate the temperature of the gas in Celsius if the pressure is changed to 2×10 to the power 4
Amahle Reply
How is energy being used in bonding?
Raymond Reply
what is acceleration
Syamthanda Reply
a rate of change in velocity of an object whith respect to time
Khuthadzo
how can we find the moment of torque of a circular object
Kidist
Acceleration is a rate of change in velocity.
Justice
t =r×f
Khuthadzo
how to calculate tension by substitution
Precious Reply
hi
Shongi
hi
Leago
use fnet method. how many obects are being calculated ?
Khuthadzo
khuthadzo hii
Hulisani
how to calculate acceleration and tension force
Lungile Reply
you use Fnet equals ma , newtoms second law formula
Masego
please help me with vectors in two dimensions
Mulaudzi Reply
how to calculate normal force
Mulaudzi
Got questions? Join the online conversation and get instant answers!
Jobilize.com Reply

Get Jobilize Job Search Mobile App in your pocket Now!

Get it on Google Play Download on the App Store Now




Source:  OpenStax, College algebra. OpenStax CNX. Feb 06, 2015 Download for free at https://legacy.cnx.org/content/col11759/1.3
Google Play and the Google Play logo are trademarks of Google Inc.

Notification Switch

Would you like to follow the 'College algebra' conversation and receive update notifications?

Ask