Given the first term and the common difference of an arithmetic sequence, find the first several terms.
Add the common difference to the first term to find the second term.
Add the common difference to the second term to find the third term.
Continue until all of the desired terms are identified.
Write the terms separated by commas within brackets.
Writing terms of arithmetic sequences
Write the first five terms of the
arithmetic sequence with
${a}_{1}=17$ and
$d=-3$ .
Adding
$\text{\hspace{0.17em}}-3\text{\hspace{0.17em}}$ is the same as subtracting 3. Beginning with the first term, subtract 3 from each term to find the next term.
The first five terms are
$\text{\hspace{0.17em}}\{17,\text{\hspace{0.17em}}14,\text{\hspace{0.17em}}11,\text{\hspace{0.17em}}8,\text{\hspace{0.17em}}5\}$
Given any the first term and any other term in an arithmetic sequence, find a given term.
Substitute the values given for
${a}_{1},{a}_{n},n$ into the formula
$\text{\hspace{0.17em}}{a}_{n}={a}_{1}+(n-1)d\text{\hspace{0.17em}}$ to solve for
$\text{\hspace{0.17em}}d.$
Find a given term by substituting the appropriate values for
$\text{\hspace{0.17em}}{a}_{1},n,\text{\hspace{0.17em}}$ and
$\text{\hspace{0.17em}}d\text{\hspace{0.17em}}$ into the formula
${a}_{n}={a}_{1}+(n-1)d.$
Writing terms of arithmetic sequences
Given
${a}_{1}=8$ and
${a}_{4}=14$ , find
${a}_{5}$ .
The sequence can be written in terms of the initial term 8 and the common difference
$d$ .
$$\left\{8,8+d,8+2d,8+3d\right\}$$
We know the fourth term equals 14; we know the fourth term has the form
${a}_{1}+3d=8+3d$ .
Some arithmetic sequences are defined in terms of the previous term using a
recursive formula . The formula provides an algebraic rule for determining the terms of the sequence. A recursive formula allows us to find any term of an arithmetic sequence using a function of the preceding term. Each term is the sum of the previous term and the common difference. For example, if the common difference is 5, then each term is the previous term plus 5. As with any recursive formula, the first term must be given.
Do we have to subtract the first term from the second term to find the common difference?
No. We can subtract any term in the sequence from the subsequent term. It is, however, most common to subtract the first term from the second term because it is often the easiest method of finding the common difference.
how we can draw three triangles of distinctly different shapes. All the angles will be cutt off each triangle and placed side by side with vertices touching
The anwser is imaginary
number if you want to know The anwser of the expression
you must arrange The expression and use quadratic formula To find the
answer
master
The anwser is imaginary
number if you want to know The anwser of the expression
you must arrange The expression and use quadratic formula To find the
answer
master
Y
master
X2-2X+8-4X2+12X-20=0
(X2-4X2)+(-2X+12X)+(-20+8)= 0
-3X2+10X-12=0
3X2-10X+12=0
Use quadratic formula To find the answer
answer (5±Root11i)/3
master
Soo sorry (5±Root11* i)/3
master
x2-2x+8-4x2+12x-20
x2-4x2-2x+12x+8-20
-3x2+10x-12
now you can find the answer using quadratic
Mukhtar
2x²-6x+1=0
Ife
explain and give four example of hyperbolic function
I think the formula for calculating algebraic is the statement of the equality of two expression stimulate by a set of addition, multiplication, soustraction, division, raising to a power and extraction of Root. U believe by having those in the equation you will be in measure to calculate it