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Key equations

Rational Function f ( x ) = P ( x ) Q ( x ) = a p x p + a p 1 x p 1 + ... + a 1 x + a 0 b q x q + b q 1 x q 1 + ... + b 1 x + b 0 ,   Q ( x ) 0

Key concepts

  • We can use arrow notation to describe local behavior and end behavior of the toolkit functions f ( x ) = 1 x and f ( x ) = 1 x 2 . See [link] .
  • A function that levels off at a horizontal value has a horizontal asymptote. A function can have more than one vertical asymptote. See [link] .
  • Application problems involving rates and concentrations often involve rational functions. See [link] .
  • The domain of a rational function includes all real numbers except those that cause the denominator to equal zero. See [link] .
  • The vertical asymptotes of a rational function will occur where the denominator of the function is equal to zero and the numerator is not zero. See [link] .
  • A removable discontinuity might occur in the graph of a rational function if an input causes both numerator and denominator to be zero. See [link] .
  • A rational function’s end behavior will mirror that of the ratio of the leading terms of the numerator and denominator functions. See [link] , [link] , [link] , and [link] .
  • Graph rational functions by finding the intercepts, behavior at the intercepts and asymptotes, and end behavior. See [link] .
  • If a rational function has x -intercepts at x = x 1 , x 2 , , x n , vertical asymptotes at x = v 1 , v 2 , , v m , and no x i = any  v j , then the function can be written in the form
f ( x ) = a ( x x 1 ) p 1 ( x x 2 ) p 2 ( x x n ) p n ( x v 1 ) q 1 ( x v 2 ) q 2 ( x v m ) q n

See [link] .

Section exercises

Verbal

What is the fundamental difference in the algebraic representation of a polynomial function and a rational function?

The rational function will be represented by a quotient of polynomial functions.

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What is the fundamental difference in the graphs of polynomial functions and rational functions?

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If the graph of a rational function has a removable discontinuity, what must be true of the functional rule?

The numerator and denominator must have a common factor.

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Can a graph of a rational function have no vertical asymptote? If so, how?

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Can a graph of a rational function have no x -intercepts? If so, how?

Yes. The numerator of the formula of the functions would have only complex roots and/or factors common to both the numerator and denominator.

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Algebraic

For the following exercises, find the domain of the rational functions.

f ( x ) = x + 1 x 2 1

All reals  x 1 ,   1

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f ( x ) = x 2 + 4 x 2 2 x 8

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f ( x ) = x 2 + 4 x 3 x 4 5 x 2 + 4

All reals  x 1 ,   2 ,   1 ,   2

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For the following exercises, find the domain, vertical asymptotes, and horizontal asymptotes of the functions.

f ( x ) = 2 5 x + 2

V.A. at x = 2 5 ; H.A. at y = 0 ; Domain is all reals x 2 5

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f ( x ) = x x 2 + 5 x 36

V.A. at x = 4 ,   9 ; H.A. at y = 0 ; Domain is all reals x 4 ,   9

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f ( x ) = 3 + x x 3 27

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f ( x ) = 3 x 4 x 3 16 x

V.A. at x = 0 ,   4 ,   4 ; H.A. at y = 0 ; Domain is all reals x 0 , 4 ,   4

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f ( x ) = x 2 1 x 3 + 9 x 2 + 14 x

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f ( x ) = x + 5 x 2 25

V.A. at x = 5 ; H.A. at y = 0 ; Domain is all reals x 5 , 5

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f ( x ) = x 4 x 6

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f ( x ) = 4 2 x 3 x 1

V.A. at x = 1 3 ; H.A. at y = 2 3 ; Domain is all reals x 1 3 .

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For the following exercises, find the x - and y -intercepts for the functions.

f ( x ) = x x 2 x

none

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f ( x ) = x 2 + 8 x + 7 x 2 + 11 x + 30

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f ( x ) = x 2 + x + 6 x 2 10 x + 24

x -intercepts none,  y -intercept  ( 0 , 1 4 )

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f ( x ) = 94 2 x 2 3 x 2 12

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For the following exercises, describe the local and end behavior of the functions.

Questions & Answers

f(x)=x/x+2 given g(x)=1+2x/1-x show that gf(x)=1+2x/3
Ken Reply
sebd me some questions about anything ill solve for yall
Manifoldee Reply
how to solve x²=2x+8 factorization?
Kristof Reply
x=2x+8
Manifoldee
×=2x-8 minus both sides by 2x
Manifoldee
so, x-2x=2x+8-2x
Manifoldee
then cancel out 2x and -2x, cuz 2x-2x is obviously zero
Manifoldee
so it would be like this: x-2x=8
Manifoldee
then we all know that beside the variable is a number (1): (1)x-2x=8
Manifoldee
so we will going to minus that 1-2=-1
Manifoldee
so it would be -x=8
Manifoldee
so next step is to cancel out negative number beside x so we get positive x
Manifoldee
so by doing it you need to divide both side by -1 so it would be like this: (-1x/-1)=(8/-1)
Manifoldee
so -1/-1=1
Manifoldee
so x=-8
Manifoldee
SO THE ANSWER IS X=-8
Manifoldee
so we should prove it
Manifoldee
x=2x+8 x-2x=8 -x=8 x=-8 by mantu from India
mantu
lol i just saw its x²
Manifoldee
x²=2x-8 x²-2x=8 -x²=8 x²=-8 square root(x²)=square root(-8) x=sq. root(-8)
Manifoldee
1KI POWER 1/3 PLEASE SOLUTIONS
Prashant Reply
hii
Amit
how are you
Dorbor
well
Biswajit
can u tell me concepts
Gaurav
Find the possible value of 8.5 using moivre's theorem
Reuben Reply
which of these functions is not uniformly cintinuous on (0, 1)? sinx
Pooja Reply
which of these functions is not uniformly continuous on 0,1
Basant Reply
solve this equation by completing the square 3x-4x-7=0
Jamiz Reply
X=7
Muustapha
=7
mantu
x=7
mantu
3x-4x-7=0 -x=7 x=-7
Kr
x=-7
mantu
9x-16x-49=0 -7x=49 -x=7 x=7
mantu
what's the formula
Modress
-x=7
Modress
new member
siame
what is trigonometry
Jean Reply
deals with circles, angles, and triangles. Usually in the form of Soh cah toa or sine, cosine, and tangent
Thomas
solve for me this equational y=2-x
Rubben Reply
what are you solving for
Alex
solve x
Rubben
you would move everything to the other side leaving x by itself. subtract 2 and divide -1.
Nikki
then I got x=-2
Rubben
it will b -y+2=x
Alex
goodness. I'm sorry. I will let Alex take the wheel.
Nikki
ouky thanks braa
Rubben
I think he drive me safe
Rubben
how to get 8 trigonometric function of tanA=0.5, given SinA=5/13? Can you help me?m
Pab Reply
More example of algebra and trigo
Stephen Reply
What is Indices
Yashim Reply
If one side only of a triangle is given is it possible to solve for the unkown two sides?
Felix Reply
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Rubben
kya
Khushnama
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Dayo Reply
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Navin
Practice Key Terms 5

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Source:  OpenStax, Algebra and trigonometry. OpenStax CNX. Nov 14, 2016 Download for free at https://legacy.cnx.org/content/col11758/1.6
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