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Not all divisions end in zero. We will examine such divisions in a subsequent subsection.

Practice set a

Perform the following divisions.

126 ÷ 7 size 12{"126" div 7} {}

18

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324 ÷ 4 size 12{"324" div 4} {}

81

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2, 559 ÷ 3 size 12{2,"559" div 3} {}

853

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5, 645 ÷ 5 size 12{5,"645" div 5} {}

1,129

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757 , 125 ÷ 9 size 12{"757","125" div 9} {}

84,125

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Division with a multiple digit divisor

The process of division also works when the divisor consists of two or more digits. We now make educated guesses using the first digit of the divisor and one or two digits of the dividend.

Sample set b

Find 2, 232 ÷ 36 size 12{2,"232" div "36"} {} .

36 2232

Use the first digit of the divisor and the first two digits of the dividend to make the educated guess.

3 goes into 22 at most 7 times.

Try 7: 7 × 36 = 252 size 12{7 times "36"="252"} {} which is greater than 223. Reduce the estimate.

Try 6: 6 × 36 = 216 size 12{6 times "36"="216"} {} which is less than 223.

The first step of a long division problem. 2232 divided by 36. 36 goes into 223 approximately 6 times, with a remainder of 7. The ones digit of 2232 is then brought down to adjoin the 7. Multiply: 6 × 36 = 216. Write 216 below 223. Subtract: 223 - 216 = 7. Bring down the 2.

Divide 3 into 7 to estimate the number of times 36 goes into 72. The 3 goes into 7 at most 2 times.

Try 2: 2 × 36 = 72 size 12{2 times "36"="72"} {} .

Long division. 2232 divided by 36. 36 goes into 223 approximately 6 times, with a remainder of 7. The ones digit of 2232 is then brought down to adjoin the 7. 36 goes into 72 exactly twice, leaving a remainder of 0.

Check : Is 2232 equal to 36 time 62? Yes.

Thus, 2, 232 ÷ 36 = 62 size 12{2,"232" div "36"="62"} {} .

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Find 2, 417 , 228 ÷ 802 size 12{2,"417","228" div "802"} {} .

802 2417228

First, the educated guess: 24 ÷ 8 = 3 size 12{"24" div 8=3} {} . Then 3 × 802 = 2406 size 12{3 times "802"="2406"} {} , which is less than 2417. Use 3 as the guess. Since 3 × 802 = 2406 size 12{3 times "802"="2406"} {} , and 2406 has four digits, place the 3 above the fourth digit of the dividend.

The first step of a long division problem. 2417228 divided by 802. 802 goes into 2417 approximately 3 times, with a remainder of 11. The hundreds digit of 2417228 is then brought down to adjoin the 11.
Subtract: 2417 - 2406 = 11.
Bring down the 2.

The divisor 802 goes into 112 at most 0 times. Use 0.

The second step of a long division problem. 802 goes into 112 0 times, so a zero is placed above, and the next digit is brought down.
Multiply: 0 × 802 = 0. Subtract: 112 - 0 = 112. Bring down the 2.

The 8 goes into 11 at most 1 time, and 1 × 802 = 802 size 12{1 times "802"="802"} {} , which is less than 1122. Try 1.

The third step of a long division problem. 802 goes into 1122 once, so a 1 is placed above and the ones digit is brought down.
Subtract 1122 - 802 = 320
Bring down the 8.

8 goes into 32 at most 4 times.

4 × 802 = 3208 size 12{4 times "802"="3208"} {} .

Use 4.

The third step of a long division problem. 2417228 divided by 802. 802 goes into 2417 approximately 3 times, with a remainder of 11. The hundreds digit of 2417228 is then brought down to adjoin the 11. 802 goes into 112 0 times, so a zero is placed above, and the next digit is brought down. 802 goes into 1122 once, so a 1 is placed above and the ones digit is brought down. 802 goes into 3208 4 times, leaving a remainder of 0.

Check: Is 2417228 equal to 3014 times 802? Yes.

Thus, 2, 417 , 228 ÷ 802 = 3, 014 size 12{2,"417","228" div "802"=3,"014"} {} .

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Practice set b

Perform the following divisions.

1, 376 ÷ 32 size 12{1,"376" div "32"} {}

43

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6, 160 ÷ 55 size 12{6,"160" div "55"} {}

112

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18 , 605 ÷ 61 size 12{"18","605" div "61"} {}

305

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144 , 768 ÷ 48 size 12{"144","764" div "48"} {}

3,016

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Division with a remainder

We might wonder how many times 4 is contained in 10. Repeated subtraction yields

10 -   4 ̲ 6 - 4 ̲ 2

Since the remainder is less than 4, we stop the subtraction. Thus, 4 goes into 10 two times with 2 remaining. We can write this as a division as follows.

2 4 10 -   8 ̲ 2
Divide: 4 goes into 10 at most 2 times. Multiply: 2 × 4 = 8. Write 8 below 0. Subtract: 10 - 8 = 2.

Since 4 does not divide into 2 (the remainder is less than the divisor) and there are no digits to bring down to continue the process, we are done. We write

2 R 2 4    10 - 8 ̲ 2 or 10 ÷ 4 = 2 R 2 2 with remainder 2

Sample set c

Find 85 ÷ 3 size 12{"85" div 3} {} .

Long division. 85 divided by 3. 3 goes into 8 twice, with a remainder of 2. The ones digit is then brought down. 3 goes into 25 8 times, with a remainder of 1.
Divide: 3 goes into 8 at most 2 times. Multiply: 2 × 3 = 6. Write 6 below 8. Subtract: 8 - 6 = 2. Bring down the 5. Divide: 3 goes into 25 at most 8 times. Multiply: 3 × 8 = 24. Write 24 below 25. Subtract: 25 - 24 = 1.

There are no more digits to bring down to continue the process. We are done. One is the remainder.

Check: Multiply 28 and 3, then add 1.

28 ×   3 ̲ 84 +   1 ̲ 85

Thus, 85 ÷ 3 = 28 R1 size 12{"85" div 3="28"`R1} {} .

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Find 726 ÷ 23 size 12{"726" div "23"} {} .

Long division. 726 divided by 23. 23 goes into 72 three times, with a remainder of 3. The ones digit is then brought down. 23 goes into 36 once, with a remainder of 13.

Check: Multiply 31 by 23, then add 13.

31 times 23 equals 713. 713 plus 13 equals 726.

Thus, 726 ÷ 23 = 31 R 13 size 12{"726" div "23"="31"````R"13"} {} .

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Practice set c

Perform the following divisions.

75 ÷ 4 size 12{"75" div 4} {}

18 R3

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346 ÷ 8 size 12{"346" div 8} {}

43 R2

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489 ÷ 21 size 12{"489" div "21"} {}

23 R6

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5, 016 ÷ 82 size 12{5,"016" div "82"} {}

61 R14

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41 , 196 ÷ 67 size 12{"41","196" div "67"} {}

614 R58

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Calculators

The calculator can be useful for finding quotients with single and multiple digit divisors. If, however, the division should result in a remainder, the calculator is unable to provide us with the particular value of the remainder. Also, some calculators (most nonscientific) are unable to perform divisions in which one of the numbers has more than eight digits.

Questions & Answers

Three charges q_{1}=+3\mu C, q_{2}=+6\mu C and q_{3}=+8\mu C are located at (2,0)m (0,0)m and (0,3) coordinates respectively. Find the magnitude and direction acted upon q_{2} by the two other charges.Draw the correct graphical illustration of the problem above showing the direction of all forces.
Kate Reply
To solve this problem, we need to first find the net force acting on charge q_{2}. The magnitude of the force exerted by q_{1} on q_{2} is given by F=\frac{kq_{1}q_{2}}{r^{2}} where k is the Coulomb constant, q_{1} and q_{2} are the charges of the particles, and r is the distance between them.
Muhammed
What is the direction and net electric force on q_{1}= 5µC located at (0,4)r due to charges q_{2}=7mu located at (0,0)m and q_{3}=3\mu C located at (4,0)m?
Kate Reply
what is the change in momentum of a body?
Eunice Reply
what is a capacitor?
Raymond Reply
Capacitor is a separation of opposite charges using an insulator of very small dimension between them. Capacitor is used for allowing an AC (alternating current) to pass while a DC (direct current) is blocked.
Gautam
A motor travelling at 72km/m on sighting a stop sign applying the breaks such that under constant deaccelerate in the meters of 50 metres what is the magnitude of the accelerate
Maria Reply
please solve
Sharon
8m/s²
Aishat
What is Thermodynamics
Muordit
velocity can be 72 km/h in question. 72 km/h=20 m/s, v^2=2.a.x , 20^2=2.a.50, a=4 m/s^2.
Mehmet
A boat travels due east at a speed of 40meter per seconds across a river flowing due south at 30meter per seconds. what is the resultant speed of the boat
Saheed Reply
50 m/s due south east
Someone
which has a higher temperature, 1cup of boiling water or 1teapot of boiling water which can transfer more heat 1cup of boiling water or 1 teapot of boiling water explain your . answer
Ramon Reply
I believe temperature being an intensive property does not change for any amount of boiling water whereas heat being an extensive property changes with amount/size of the system.
Someone
Scratch that
Someone
temperature for any amount of water to boil at ntp is 100⁰C (it is a state function and and intensive property) and it depends both will give same amount of heat because the surface available for heat transfer is greater in case of the kettle as well as the heat stored in it but if you talk.....
Someone
about the amount of heat stored in the system then in that case since the mass of water in the kettle is greater so more energy is required to raise the temperature b/c more molecules of water are present in the kettle
Someone
definitely of physics
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how many start and codon
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what is field
Felix Reply
physics, biology and chemistry this is my Field
ALIYU
field is a region of space under the influence of some physical properties
Collete
what is ogarnic chemistry
WISDOM Reply
determine the slope giving that 3y+ 2x-14=0
WISDOM
Another formula for Acceleration
Belty Reply
a=v/t. a=f/m a
IHUMA
innocent
Adah
pratica A on solution of hydro chloric acid,B is a solution containing 0.5000 mole ofsodium chlorid per dm³,put A in the burret and titrate 20.00 or 25.00cm³ portion of B using melting orange as the indicator. record the deside of your burret tabulate the burret reading and calculate the average volume of acid used?
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how do lnternal energy measures
Esrael
Two bodies attract each other electrically. Do they both have to be charged? Answer the same question if the bodies repel one another.
JALLAH Reply
No. According to Isac Newtons law. this two bodies maybe you and the wall beside you. Attracting depends on the mass och each body and distance between them.
Dlovan
Are you really asking if two bodies have to be charged to be influenced by Coulombs Law?
Robert
like charges repel while unlike charges atttact
Raymond
What is specific heat capacity
Destiny Reply
Specific heat capacity is a measure of the amount of energy required to raise the temperature of a substance by one degree Celsius (or Kelvin). It is measured in Joules per kilogram per degree Celsius (J/kg°C).
AI-Robot
specific heat capacity is the amount of energy needed to raise the temperature of a substance by one degree Celsius or kelvin
ROKEEB
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Source:  OpenStax, Fundamentals of mathematics. OpenStax CNX. Aug 18, 2010 Download for free at http://cnx.org/content/col10615/1.4
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