2.5 Rules of exponents  (Page 2/2)

$\frac{y^9}{y^5}$

$\frac{a^7}{a}$

$\frac{{(x+6)}^5}{{(x+6)}^3}$

$\frac{26x^4{y}^6{z}^2}{13x^2{y}^{2}z}$

$\frac{y^7}{y^3}$

$\frac{6x^4}{2x^3}$

$\frac{14a^7}{7a^2}$

$\frac{26x^2{y}^5}{4x{y}^2}$

$\frac{36a^4{b}^3{c}^8}{8a{b}^3{c}^6}$

$\frac{51{(a-4)}^3}{17(a-4)}$

$\frac{52a^7{b}^3{(a+b)}^8}{26a^{2}b{(a+b)}^8}$

$\frac{a^n}{a^3}$

$\frac{14x^r{y}^p{z}^q}{2x^r{y}^h{z}^5}$

$3^2\cdot 3^3$

$5^2\cdot 5^4$

$9^0\cdot 9^2$

$7^3\cdot 7^0$

$2^4\cdot 2^5$

$x^5{x}^4$

$x^2{x}^3$

$a^9{a}^7$

$y^5{y}^7$

$m^{10}{m}^2$

$k^8{k}^3$

$y^3{y}^4{y}^6$

$3x^2\cdot 2x^5$

$a^2{a}^3{a}^8$

$4y^4\cdot 5y^6$

$2a^3{b}^2\cdot 3ab$

$12x{y}^3{z}^2\cdot 4x^2{y}^{2}z\cdot 3x$

$(3ab)(2a^{2}b)$

$(4x^2)(8x{y}^3)$

$(2xy)(3y)(4x^2{y}^5)$

$\left(\frac{1}{4}{a}^2{b}^4\right)\left(\frac{1}{2}{b}^4\right)$

$\left(\frac{3}{8}\right)\left(\frac{16}{21}{x}^2{y}^3\right)(x^3{y}^2)$

$\frac{8^5}{8^3}$

$\frac{6^4}{6^3}$

$\frac{2^9}{2^4}$

$\frac{4^{16}}{4^{13}}$

$\frac{x^5}{x^3}$

$\frac{y^4}{y^3}$

$\frac{y^9}{y^4}$

$\frac{k^{16}}{k^{13}}$

$\frac{x^4}{x^2}$

$\frac{y^5}{y^2}$

$\frac{m^{16}}{m^9}$

$\frac{a^9{b}^6}{a^5{b}^2}$

$\frac{y^3{w}^{10}}{y{w}^5}$

$\frac{m^{17}{n}^{12}}{m^{16}{n}^{10}}$

$\frac{x^5{y}^7}{x^3{y}^4}$

$\frac{15x^{20}{y}^{24}{z}^4}{5x^{19}yz}$

$\frac{e^{11}}{e^{11}}$

$\frac{6r^4}{6r^4}$

$\frac{x^0}{x^0}$

$\frac{a^0{b}^0}{c^0}$

$\frac{8a^4{b}^0}{4a^3}$

$\frac{24x^4{y}^4{z}^0{w}^8}{9xy{w}^7}$

$t^2(y^4)$

$x^3\left(\frac{x^6}{x^2}\right)$

$a^4{b}^6\left(\frac{a^{10}{b}^{16}}{a^5{b}^7}\right)$

$3a^2{b}^3\left(\frac{14a^2{b}^5}{2b}\right)$

$\frac{{(x+3y)}^{11}{(2x-1)}^4}{{(x+3y)}^3(2x-1)}$

$\frac{40x^5{z}^{10}{(z-x^4)}^{12}{(x+z)}^2}{10z^7{(z-x^4)}^5}$

$x^n{x}^r$

$a^x{b}^y{c}^{5z}$

$x^n\cdot x^{n+3}$

$\frac{x^{n+3}}{x^n}$

$\frac{x^{n+2}{x}^3}{x^4{x}^n}$

$y^{\Delta }{y}^{\nabla }$

$a^{\Delta }{a}^{\nabla }{b}^{\square }{b}^{\diamond }$

( [link] ) What natural numbers can replace $x$ so that the statement $-5<x\le 3$ is true?

( [link] ) Use the distributive property to expand $4x(2a+3b)$ .

( [link] ) Express $xxxyyyy(a+b)(a+b)$ using exponents.

( [link] ) Find the value of $4^2+3^2\cdot 2^3-10\cdot 8$ .

( [link] ) Find the value of $\frac{4^2+{(3+2)}^2-1}{2^3\cdot 5}+\frac{2^4(3^2-2^3)}{4^2}$ .